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Nutka1998 [239]
3 years ago
5

Identify from the following list of molecules and ions which behave as Lewis acids: CO2, NH3, BCl3, Fe3+. (A) CO2 and NH3 (B) NH

3 and BCl3 (C) CO2 and Fe3+ (D) CO2, BCl3, and Fe3+ (E) CO2, NH3, BCl3, and Fe3+
Chemistry
1 answer:
Anettt [7]3 years ago
6 0

Answer : The correct option is, (D) CO₂, BCl₃, and Fe³⁺

Explanation :

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

(a) CO_2

It is a Lewis-acid because it can accepts electron pairs.

(b) NH_3

It is not a Lewis-acid because it can not accepts electron pairs but it is a base because it can donates and accept hydrogen ion.

(c) BCl_3

It is a Lewis-acid because it can accepts electron pairs because it has an incomplete octet and an empty 2p orbital.

(d) Fe^{3+}

It is a Lewis-acid because it can accepts electron pairs.

Hence, the ions which behave as Lewis acids are, CO₂, BCl₃, and Fe³⁺

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4 years ago
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Método científico: El trabajo científico se caracteriza por ser planificado, con objetivos iniciales y que habitualmente se dan
Snezhnost [94]

Answer:

Ver explicación

Explanation:

El método científico se refiere al patrón establecido de resolución de un problema científico. Los siguientes son pasos importantes en el método científico;

Haz una observación.

formular preguntas relevantes.

elabore una hipótesis que pueda ser probada.

Diseña un experimento.

Prueba la hipótesis usando tu diseño experimental.

Teniendo en cuenta ambos escenarios, el último caso en el que estudiantes de diferentes capacidades trabajan juntos para resolver un problema refleja mejor el método científico porque pueden hacerse preguntas entre sí y llegar a hipótesis comprobables que pueden demostrarse como verdaderas o falsas mediante experimentos.

8 0
3 years ago
The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.
enot [183]

Answer:

\large \boxed{\text{21.6 L}}

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:        180.16

         C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g:      24.5

(a) Moles of C₆H₁₂O₆

\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}

(b) Moles of CO₂

\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37  °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}

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Answer:

10

Explanation:

I did that already. You got beo

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