(CREATE A TESTABLE QUESTION) my four substances are water, isopropanol alcohol, Penny(copper), and, Nickle(zinc)
1 answer:
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<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.
<u>Explanation:</u>
To calculate the number of moles from molarity, we use the equation:
Molarity of barium chloride = 0.113 M
Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
1 mole of barium chloride is producing 1 mole of barium sulfate.
So, 0.00286 moles of barium chloride will produce = of barium sulfate.
Now, to calculate the mass of barium sulfate, we use the equation:
Molar mass of barium sulfate = 233.38 g/mol
Moles of barium sulfate = 0.00286 moles
Putting values in above equation, we get:
Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams
Answer:
1.56 mol H₂
Explanation:
Mg₃(Si₂O₅)₂(OH)₂
<em>There are 4 Si moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>. With that in mind we can <u>calculate how many Mg₃(Si₂O₅)₂(OH)₂ moles are there in the sample</u>, using the <em>given number of silicon moles</em>:
- 3.120 mol Si *
= 0.78 mol Mg₃(Si₂O₅)₂(OH)₂
Then we can <u>convert Mg₃(Si₂O₅)₂(OH)₂ moles into hydrogen moles</u>, keeping in mind that <em>there are 2 hydrogen moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>:
- 0.78 mol Mg₃(Si₂O₅)₂(OH)₂ * 2 = 1.56 mol H₂