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3 years ago

An inclined plane that moves and has one or two sloping sides forms a machine called a ____.

Chemistry

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

If i remember correctly it should be a wedge

Alexandra [31]3 years ago

6 0

Answer:

wedge

Explanation:

trust me

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Predict the outcome of this reaction. Balancing doesn't matter. Mg + H2O -->

ELEN [110]

Answer:

MgO + H₂

Explanation:

The products of reaction is MgO and hydrogen gas.

This is a single displacement reaction.

In this reaction, the possibility of the reaction is determined by position of the atoms on the activity series.

Mg is higher than H on the activity series, so it is more reactive and it then displaces the hydrogen in water;

Mg + H₂O → MgO + H₂

7 0

2 years ago

1. A substance, A₂B, has the composition by mass of 60% A and 40% B. What is the composition of AB₂ by mass?

Lubov Fominskaja [6]

This may help you
Use an arbitrary mass, 100 g is an easy number to work with. 60% of 100 g is 60 g, there are two A's. Each A is 30 g 40 g is B, and there is only one, so B is 40 g. AB2, would have a mass of 30 g + 2*40 g = 110 g The new percent by mass composition of A is: 30g110g∗100%=27.3% The new percent by mass composition of B is: 80g110g∗100%=72.7%

8 0

2 years ago

Which statement best describes the pH of pure water? It is neutral because the concentration of hydronium ions equals that of hy

stira [4]

The pH of pure water has been best described as neutral pH with equal hydronium and hydroxide ions. Thus, option A is correct.

pH has been described as the measurement of hydrogen ions in a solution. The pH has been measured on a scale of 1-14. pH 7 has been the neutral pH.

The higher hydronium ion concentration tends to move the pH from 7 towards 1. The higher hydroxide ion concentration tends to move the pH above 7.

The neutral pH has been neither acidic nor basic with the equal constituents of hydronium and hydroxide ion in the solution.

Thus, the pH of pure water has been 7. It has neutral pH with equal hydronium and hydroxide ions. Thus, option A is correct.

For more information about the pH of the solution, refer to the link:

brainly.com/question/4975103

4 0

2 years ago

Read 2 more answers

What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not

Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] -Where A⁻ is acetate ion and HA is acetic acid-

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

1,7378 = [A⁻]/[HA] (1)

As concentration of buffer is 0,15M, it is possible to write:

[A⁻] + [HA] = 0,15M (2)

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need acetic acid 0,055M and acetate 0,095M to obtain the buffer you need.

i hope it helps!

7 0

3 years ago

Calculate the following: [6.6 x <img src="https://tex.z-dn.net/?f=10%5E%7B-2%7D" id="TexFormula1" title="10^{-2}" alt

anyanavicka [17]

0.066-0.0069= 0.0591

4 0

2 years ago