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3 years ago

Is anybody good in Chemistry that can help me with this?

Chemistry

1 answer:

sesenic [268]3 years ago

5 0

Answer:

just replace the 9 mole with 3.68 g of Al .

I think it will help you.

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A loose, icy body with a long, narrow orbit is?

Firdavs [7]

A loose, icy body with a long, narrow orbit is a comet

3 0

3 years ago

Read 2 more answers

The carbon dioxide exhaled by astronauts can be removed from a spacecraft by reacting it with lithium hydroxide (LiOH). The reac

maks197457 [2]

Two astronauts would exhale about 40 moles of carbon dioxide daily.

Carbon dioxide reacts with lithium hydroxide in a 1 : 2 mole ratio. Set up a proportion:

1 : 2 = 40 : x

Then, find x: 12=40x

 Cross multiply. x = 80 moles of LiOH per day for both astronauts

8 0

3 years ago

A 1.2516 gram sample of a mixture of caco3 and na2so4 was analyzed by dissolving the sample and completely precipitating the ca

Dennis_Churaev [7]

Answer:

0.009725 moles of H2C2O4

0.009725 moles CaCO3

Mass percentage = 77.77%

Explanation:

Step 1: The balanced equation

2MnO4- +5C2H2O4+6H+ →2Mn2+ +10CO2+8H2O

We can see that for 2 moles of Mno4- consumed , there is 5 moles of C2H2O4 needed and 6 moles H+ to produce 2 moles Mn2+, 10 moles of CO2 and 8 moles of H2O

Step 2: Calculate moles of MnO4-

Molarity = Moles/volume

Moles of Mno4- = Molarity of MnO4- * Volume of Mno4-

Moles of Mno4- = 0.1092M * 35.62 *10^-3 L

Moles of MnO4- = 0.00389 moles

Step 3: Calculate moles of H2C2O4

Since there is needed 5 moles of C2H2O4 to consume 2 moles of MnO4-

then for 0.00389 moles of MnO4-, there is 5/2 *0.00389 = 0.009725 moles of H2C2O4

Step 4: Calculate moles of CaCO3

moles of H2C2O4 = moles CaCO3, therefore, 0.009725 moles H2C2O4 = 0.009725 moles CaCO3

Step 5: Calculate mass of CaCO3

Molar mass of CaCO3 = 100.09 g/mole

Mass of CaCO3 = moles of CaCO3 * Molar mass of CaCO3

Mass of CaCO3 = 0.009725 moles * 100.09 g/mole = 0.9734 g

Step 6: Calculate percentage by weight of CaCO3

Mass of CaCO3 = 0.9734g

Mass of original sample = 1.2516g

Mass percentage = 0.9734/1.2516 *100% = 77.77%

6 0

3 years ago

How many moles of helium gas are contained in a 4.0 L flask at STP

Ratling [72]

First, you convert liters to moles.
Usually you have to go to grams but this is STP.

Get moles directly by dividing the 4 by STP (22.4)
$\frac{4}{22.4} =0.17857142857$
About $1.8*10^{-1}$ or 0.18 moles whichever your teacher prefers

3 0

3 years ago

A buffer solution is prepared by dissolving equal amounts of ascorbic acid and sodium ascorbate, the conjugate base, in water. T

Gnom [1K]

THANKS

$\color{pink} \rule{500pt}{100000000pt}$

8 0

2 years ago

Is anybody good in Chemistry that can help me with this?​

Is anybody good in Chemistry that can help me with this?