Im pretty sure its A cuz is closer to the earth.
Answer:
a) 
Now we can replace the velocity for t=1.75 s

For t = 3.0 s we have:

b) 
And we can find the positions for the two times required like this:
And now we can replace and we got:

Explanation:
The particle position is given by:

Part a
In order to find the velocity we need to take the first derivate for the position function like this:

Now we can replace the velocity for t=1.75 s

For t = 3.0 s we have:

Part b
For this case we can find the average velocity with the following formula:

And we can find the positions for the two times required like this:
And now we can replace and we got:

Answer: 2.49×10^-3 N/m
Explanation: The force per unit length that two wires exerts on each other is defined by the formula below
F/L = (u×i1×i2) / (2πr)
Where F/L = force per meter
u = permeability of free space = 1.256×10^-6 mkg/s^2A^2
i1 = current on first wire = 57A
i2 = current on second wire = 57 A
r = distance between both wires = 26cm = 0.26m
By substituting the parameters, we have that
Force per meter = (1.256×10^-6×57×57)/ 2×3.142 ×0.26
= 4080.744×10^-6/ 1.634
= 4.080×10^-3 / 1.634
= 2.49×10^-3 N/m
They flow i guess but dont quote me on that
Answer:
Explanation:
Using the formula : E = mc²
Where m = mass = 6.8 × 10^-6 kg
c = speed of light = 3 ×10^8 m/s
The amount of joules of energy that would be produced equals :
Plugging in our values :
E = mc²
E = (6.8 × 10^-6) kg × (3 ×10^8)²m/s
E = (6.8 × 10^-6) kg × 9 × 10^16 m/s
E = 61.2 × 10^(-6 + 16)
E = 61.2 × 10^10 J