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Valentin [98]
3 years ago
10

P4 +6Br2 --> 4PBr3

Chemistry
2 answers:
Sever21 [200]3 years ago
8 0

Answer:

\boxed {\boxed {\sf 1 \ mole \ P_4 consumed \ to \ 4 \ moles \ PBr_3 \  produced}}

Explanation:

To find the mole ratio, we must use the coefficients.

P_4+6Br_2 \rightarrow 4PBr_3

This equation is balanced (4 atoms of P and 12 atoms of Br on both sides), so we can go straight to the coefficients.

  • P₄ doesn't have a coefficient, so 1 is implied
  • Br₂ has a coefficient of 6
  • PBr₃ has a coefficient of 4

So according to the coefficients above, for every 1 mole of P₄ that is consumed, 4 moles of PBr₃ are produced. Therefore, the ratio is 1 mole P₄ to 4 moles of PBr₃.

grin007 [14]3 years ago
6 0

Answer:

1 mole of P₄ consumed:4 moles of PBr₃ produced

Explanation:

Look at the coefficients in the balanced chemical equation to determine the ratios. For every 1 mole of P₄ consumed (P₄ has a coefficient of 1), 4 moles of PBr₃ would be produced (PBr₃ has a coefficient of 4).

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Answer:

\Delta H for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

C(graphite)+O_{2}(g)\rightarrow CO_{2}(g) \Delta H_{1}= -393.5 kJ

2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l) \Delta H_{2}= (2\times -285.8)kJ

CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)  \Delta H_{3}= 726.4 kJ

---------------------------------------------------------------------------------------------------

C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ

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4 years ago
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When 280. mL of 1.50 × 10⁻⁴ M hydrochloric acid is added to 135 mL of 1.75 × 10⁻⁴ M Mg(OH)₂, the resulting solution will be?
goldfiish [28.3K]

Answer:

B is the correct answer!

Explanation:

Balanced equation is Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O

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