Answer:
Explanation:
The charge on one object, 
The distance between the charges, r = 0.22 m
The force between the charges, F = 4,550 N
Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :
So, the charge on the other sphere is 
.
Answer:
a) x = 660 m
, b) λ = 0.330 m
, c) precision is 0.1 cm
, d) Δf= n Δt/ t²
Explanation:
a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is
v = x / t
x = v t
x = 330 2
x = 660 m
b) the speed of sound is
v = λ f
λ = v / f
λ = 330/1000
λ = 0.330 m
c) a measuring tape must be used to measure the wavelength, the precision is 0.1 cm
.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency
.f = n / t
Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s
Δf / f = Δt / t
Δf = Δt /t f
Δf= n Δt/ t²
Betelgeuse is a class of Supergiant stars and they are 1000 times bigger than our own sun, they typically had 1000 radii. Barnard's stars belongs to Main Sequence Star in which our sun belong. Our Sun is almost seven time larger than a Barnard's star. Barnard's star typically has only 0.15 Solar radii. Our Sun has 1.0 solar radii.
Answer: 
Explanation:
Given
If an object reaches the topmost point i.e. it cannot travel beyond that point as its velocity is zero at the topmost point
As some velocity is needed to move the object, so velocity at topmost point is zero
