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Kazeer [188]
3 years ago
10

Ryan is driving his car to band practice. His speed is 55 mph. Splat! A bug smashes against the windshield, and bug "guts" are e

verywhere. Gross! Which scenario is true?
The windshield exerts a greater force on the bug than the bug exerts on the windshield.
The bug exerts a greater force on the windshield than the windshield exerts on the bug.
The force that the windshield exerts on the bug and the force that the bug exerts on the windshield are the same magnitude.
Physics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

<h2>The force that the windshield exerts on the bug and the force that the bug exerts on the windshield are the same magnitude.</h2>

Explanation:

In this context, both forces are the same but in opposite directions, according to the third Newton's Law: Every action has an equal and opposite reaction. One clear example is when we are sitting, our weight has an opposite reaction, which is equal, the normal force, totally opposite to the weight.

Therefore, in this case, the third answer is the correct one. Because the force exerted by the bug must be equal and opposite to the exerted by the windshield, if they weren't opposite, the bud wouldn't be smashed.

meriva3 years ago
5 0

Answer:

The answer should be B.

Explanation:

If you punch a wall, no wonder your fist will hurt. The wall adds as much force back into your arm as you did to the wall.

However much force you apply to something, an equal amount of force will come right back at you.

However, in cases like your one, I highly doubt that the bug was flying 55mph. Therefore, since the car has more mass and was traveling faster than the bug, the car has applied more force to the bug than the bug did to it.

Good luck, and I hope that this helps.

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C. If you knew the pressure, volume, and temperature of the air in the
densk [106]

Answer:

Explanation:

First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin).

5 0
3 years ago
A sinusoidal sound wave moves through a medium and is described by the displacement wave function
ZanzabumX [31]

By applying the wave equation we know that the maximum speed of the element's oscillatory motion is 1716 micrometer / s.

We need to know about wave equations to solve this problem. The displacement of the wave on the y-axis can be explained by the wave equation

y = A cos (kx - ωt)

where y is y-axis displacement, A is amplitude, k is wave number, x is x-axis displacement, ω is angular speed and t is time.

the wavenumber and angular speed of the wave equation can be determined respectively by

k = 2π / λ

ω = 2πf

where k is the wavenumber, λ is wavelength and f is frequency.

From the question above, we know that:

y = 2.00cos (15.7x - 858t)

v = dy / dt

v = d(2.00cos (15.7x - 858t)) / dt

v = -858 x (-2.00sin(15.7x - 858t))

v = 1716 sin(15.7x - 858t) micrometer/s

maximum velocity can be reached when (sinθ = 1), hence

v = 1716 sin(15.7x - 858t)

v = 1716 x 1

v = 1716 micrometer / s

For more on wave equation on: brainly.com/question/25699025

#SPJ

4 0
2 years ago
g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the
sdas [7]

Answer:

The vertical distance is  d = \frac{2}{k} *[mg + f]

Explanation:

From the question we are told that

   The mass of the cylinder is  m

    The kinetic frictional force is  f

Generally from the work energy theorem

    E  =  P +  W_f

Here E the the energy of the spring which is increasing and this is mathematically represented as

       E =  \frac{1}{2} * k  *  d^2

Here k is the spring constant

        P is the potential energy of the cylinder which is mathematically represented as

     P  = mgd

And

     W_f  is the workdone by friction which is mathematically represented as

      W_f  =  f *  d

So

    \frac{1}{2} * k  *  d^2 =  mgd +  f *  d

=>    \frac{1}{2} * k  *  d^2 =  d[mg +  f    ]

=>  \frac{1}{2} * k  *  d =  [mg +  f    ]

=> d = \frac{2}{k} *[mg + f]

5 0
4 years ago
Enter an expression in the box to Write the equation of the line perpendicular to y=-3x-1 that passes through the point (3,4).
Dafna11 [192]

Answer: -3x+13

Explanation:

4 0
3 years ago
A baseball pitcher throws a 0.14 kg ball toward a batter who is 18 m away.
Olin [163]

Answer:

A. 112 J

Explanation:

KE = ½mv² = ½(0.14)40² = 112 J

5 0
3 years ago
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