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Kazeer [188]
3 years ago
10

Ryan is driving his car to band practice. His speed is 55 mph. Splat! A bug smashes against the windshield, and bug "guts" are e

verywhere. Gross! Which scenario is true?
The windshield exerts a greater force on the bug than the bug exerts on the windshield.
The bug exerts a greater force on the windshield than the windshield exerts on the bug.
The force that the windshield exerts on the bug and the force that the bug exerts on the windshield are the same magnitude.
Physics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

<h2>The force that the windshield exerts on the bug and the force that the bug exerts on the windshield are the same magnitude.</h2>

Explanation:

In this context, both forces are the same but in opposite directions, according to the third Newton's Law: Every action has an equal and opposite reaction. One clear example is when we are sitting, our weight has an opposite reaction, which is equal, the normal force, totally opposite to the weight.

Therefore, in this case, the third answer is the correct one. Because the force exerted by the bug must be equal and opposite to the exerted by the windshield, if they weren't opposite, the bud wouldn't be smashed.

meriva3 years ago
5 0

Answer:

The answer should be B.

Explanation:

If you punch a wall, no wonder your fist will hurt. The wall adds as much force back into your arm as you did to the wall.

However much force you apply to something, an equal amount of force will come right back at you.

However, in cases like your one, I highly doubt that the bug was flying 55mph. Therefore, since the car has more mass and was traveling faster than the bug, the car has applied more force to the bug than the bug did to it.

Good luck, and I hope that this helps.

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3 years ago
Select all that apply. which of the following astronomers supported the sun-centered system? tycho brahe johannes kepler coperni
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what is the magnitude of the electric force between charges of 0.25 C and 0.11 C at a separation of 0.88 m? if the separation be
leonid [27]
F = k \cdot \frac{q_1 q_2}{d} = 9 \cdot 10^{9} \cdot \frac{0.25 \cdot 0.11}{0.88} =  144 \cdot 5^{9} \ N.

If the separation between the charges is increased then the magnitude of the force will increase in fact how the distance is being used in that formula.
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3 years ago
A truck has shock absorbers with a spring constant of 24200 N/m. When it hits a bump, it oscillates at 0.429 Hz. What is the mas
siniylev [52]

Answer:

3331.5 kg

Explanation:

Given:

Spring constant of the spring (k) = 24200 N/m

Frequency of oscillation (f) = 0.429 Hz

Let the mass be 'm' kg.

Now, we know that, a spring-mass system undergoes Simple Harmonic Motion (SHM). The frequency of oscillation of SHM is given as:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

Rewrite the above equation in terms of 'm'. This gives,

2\pi f=\sqrt{\frac{k}{m}}\\\\Squaring\ both\ sides,\ we\ get:\\\\(2\pi f)^2=\frac{k}{m}\\\\m=\frac{k}{4\pi^2 f^2}

Now, plug in the given values and solve for 'm'. This gives,

m=\frac{24200\ N/m}{4\pi^2\times (0.429\ Hz)^2 }\\\\m=\frac{24200\ N/m}{4\pi^2\times 0.184\ Hz^2}\\\\m\approx3331.5\ kg

Therefore, the mass of the truck is 3331.5 kg.

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