All categories

3 years ago

Describes the relationship between the free energy change, the reaction quotient, and the equilibrium constant.

Physics

1 answer:

LUCKY_DIMON [66]3 years ago

4 0

Explanation:

Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol Q.

The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol K.

The relationship between Gibbs free energy change and reaction quotient of the reaction is:

$\Delta G=\Delta G^o+RT ln Q$ ......(1)

where,

$\Delta G$ = Gibbs free energy change

$\Delta G^o$ = Standard Gibbs free energy change

R = Gas constant

T = Temperature

At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:

$\Delta G^o=-RT ln Q$ ...(2)

You might be interested in

Two compact sources of sound oscillate in phase with a frequency of 100 Hz. At a point 5.00m from one source and 5.85 m from the

antoniya [11.8K]

Answer:

(a)1.557 radian (b) 1.424 A

Explanation:

Frequency of oscillation of sound = 100 Hz

$\Delta r=5.85-5=0.85m$

(a)The phase difference is given by $\frac{2\pi \Delta r}{λ}$ where v is the velocity of sound in air

So phase difference $\frac{2\pi \Delta rf}{v}$ as $\lambda =\frac{v}{f}$

So phase difference $=\frac{2\times 3.14\times 0.85\times 100}{343}=1.557radian$

(b) The resultant amplitude is given by $2Acos\frac{\Phi }{2}=2\times A\times cos\frac{1.557}{2}=1.424A$

5 0

3 years ago

What is the phase of the Moon if it . . .

anzhelika [568]

Answer:

Waxing Gibbous

Third quarter

Waning Gibbous

Explanation:

If moon rises at 3:00 pm then the phase of the moon will be "Waxing Gibbous".

This is because, the moon is actually not fully illuminated but has achieved more than half of its full illumination.

If the moon is highest in the sky at sunrise then the phase of the Moon will be the "Third quarter"

This is because of the fact that at this position moon will rise at midnight, thus it will be at the highest point at the time of the sunrise.

If the moon sets at 10:00 am then the phase of the Moon is "Waning Gibbous"

This is because of the fact that at this position the Moon is moving towards becoming new Moon but at the same time, the moon is illuminated more than its half illumination.

8 0

3 years ago

A pendulum with a length of 1 meter is released from an initial angle of 15.0° after 1000s its amplitude has been reduced by fri

Setler [38]

Answer:

0.366×10^{-3} / s

Explanation:

θ = θmax e^{-bt/2m}

Given that

θ = 5.50°

θmax = 15.0°

So that we have

ln (θ / θmax) = -bt /2m

= - ln(5.50°/ 15.0°) / 1000s = b /2m

= b / 2m = 0.366×10^{-3} / s

3 0

3 years ago

A transformer has a primary coil with 375 turns of wire and a secondary coil with 1,875 turns. An AC voltage source connected ac

Sonbull [250]

Answer:

The rms voltage (in V) measured across the secondary coil is 459.62 V

Explanation:

Given;

number of turns in the primary coil, Np = 375 turns

number of turns in the secondary coil, Ns = 1875 turns

peak voltage across the primary coil, Ep = 130 V

peak voltage across the secondary coil, Es = ?

$\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V$

The rms voltage (in V) measured across the secondary coil is calculated as;

$V_{rms} = \frac{V_0}{\sqrt{2} } = \frac{E_s}{\sqrt{2} } \\\\V_{rms} = \frac{650}{\sqrt{2} } = 459.62 \ V$

Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V

7 0

3 years ago

Why is it good practice for scientists to repeat trails

tensa zangetsu [6.8K]

It makes the data thet they collect more reliable so if they need the data again, they have already tested it a few times so therefor they know that it is right.

8 0

4 years ago