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Fed [463]
3 years ago
8

How to make snf62- lewis structure in aleks?

Physics
1 answer:
umka21 [38]3 years ago
4 0
 Sn is in group 4 so has 4 electrons in the outer shell (draw<span> these as dots) Add 1 more electron from each bond to F (+6) </span>
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A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
Sergeeva-Olga [200]

Answer:

33.23 m

Explanation:

At the point where both objects will meet, the vertical height will be equal.

From the equations of motion, the vertical height of the body falling at any time is given as

(y - y₀) = ut + ½gt²

y = vertical height at any time T

y₀ = initial height of the object = 81.5 m

u = initial velocity = 0 m/s (body was dropped)

g = -9.8 m/s²

(y - 81.5) = 0 - 4.9T²

y = 81.5 - 4.9T² (eqn 1)

For an object thrown up, the vertical height of the body at any time, t, is given as

(y - y₀) = ut + ½gt²

y = vertical height of the object at any time t

y₀ = initial height of the object = 0 m

u = initial velocity = 40 m/s

g = -9.8 m/s²

y = 40t - 4.9t² (eqn 2)

At the point where the two objects meet, we equate eqn 1 and eqn 2

y = y

81.5 - 4.9T² = 40t - 4.9t²

But T = (t + 2.2) (Since object 2 was dropped 2.2 s after object 1)

81.5 - 4.9(t + 2.2)² = 40t - 4.9t²

81.5 - 4.9(t² + 4.4t + 4.84) = 40t - 4.9t²

81.5 - 4.9t² - 21.56t - 23.716 = 40t - 4.9t²

81.5 - 21.56t - 23.716 - 40t = 0

57.784 = 61.56t

t = (57.784/61.56) = 0.93866 = 0.94 s

Therefore, the vertical height at t = 0.93866 s is

y = (40×0.93866) - 4.9(0.93866²) = 33.23 m

Hope this Helps!!!

5 0
3 years ago
Which one of the following statements about sulfric acid is correct?
Veseljchak [2.6K]

Answer:

Which one of the following statements about sulphuric acid is correct?

Sulphuric acid is a strong oxidizing agent

Explanation:

Sulphuric acid is a very strong oxidizing agent, also it is know for its allotope of S8

5 0
3 years ago
What happens to light when it strikes the inside surface of a smooth, curved mirror? It bounces in random directions. It bounces
kotykmax [81]
This is a concave mirror you're talking about, so all of the points are going to converge to a single focal point. Therefore the answer would be that it bounces back toward a single spot
5 0
3 years ago
Read 2 more answers
You are testing a new amusement park roller coaster with an empty car with a mass of 108kg. One part of the track is a vertical
xenn [34]

Answer:

-4892 J

Explanation:

The work done by friction is equal to the difference in mechanical energy of the car between the bottom of the loop (point A) and the top of the loop (point B).

The mechanical energy of the car at point A is

E_A = \frac{1}{2}mv_A^2 + mgh_A

where

m=108 kg is the mass of the car

v_A = 25.0 m/s is the speed at point A

h_A=0 is the height of the car at point A (zero because it is at the bottom of the loop)

Substituting into the equation, we find

E_A = \frac{1}{2}(108 kg)(25.0 m/s)^2 + (108 kg)(9.8 m/s^2)(0)=33,750J

The mechanical energy of the car at point B is

E_B = \frac{1}{2}mv_B^2 + mgh_B

where

m=108 kg is the mass of the car

v_B = 8.0 m/s is the speed at point B

h_B=24.0 m (twice the radius) is the height of the car at point B, at the top of the loop

Substituting into the equation, we find

E_B = \frac{1}{2}(108 kg)(8.0 m/s)^2 + (108 kg)(9.8 m/s^2)(24.0 m)=28,858J

So, the work done by friction is

W=E_B-E_A=28,858 J-33,750 J=-4,892 J

And the work is negative because it is done against the motion of the car.

6 0
3 years ago
A gas is put into a closed container. The container and the gas inside it are heated. What will happen to the pressure inside th
arlik [135]

Answer:

Explanation:

Plug

3 0
3 years ago
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