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swat32
3 years ago
5

A supersaturated solution can be prepared by dissolving solute in solvent while adding ______. A supersaturated solution contain

s more ______ than can ordinarily be dissolved in the solvent at room temperature. A solution may remain supersaturated until _______ is initiated, often by adding solid to the solution or by allowing solvent to evaporate.
Chemistry
1 answer:
Delicious77 [7]3 years ago
4 0

Answer:

Heat, solutes and high temperature.

Explanation:

A supersaturated solution can be formed by dissolving solute more solute in solvent by increasing temperature of the solution. A supersaturated solution contains more quantity of solutes than can be dissolved in the solvent at room temperature. A solution may remain supersaturated until the solution has high temperature and when the temperature started lower, the extra dissolve solutes begin undissolved and remain suspended in the solution.

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Can someone solve this problem 5
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Answer:

2

Step-by-step explanation:

A. Moles before mixing

<em>Beaker I: </em>

Moles of H⁺ = 0.100 L × 0.03 mol/1 L

                   = 3 × 10⁻³ mol

<em>Beaker II: </em>

Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.

        H⁺][OH⁻] = 1 × 10⁻¹⁴   Divide each side by [H⁺]

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E/mol:    2 × 10⁻³          0

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You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.


C. pH

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 pH = -log[H⁺ ]

       = -log(1 × 10⁻²)

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Mass is related to the number of particles, but not directly related to volume so this option is a bit ambiguous.</span>
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