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swat32
3 years ago
5

A supersaturated solution can be prepared by dissolving solute in solvent while adding ______. A supersaturated solution contain

s more ______ than can ordinarily be dissolved in the solvent at room temperature. A solution may remain supersaturated until _______ is initiated, often by adding solid to the solution or by allowing solvent to evaporate.
Chemistry
1 answer:
Delicious77 [7]3 years ago
4 0

Answer:

Heat, solutes and high temperature.

Explanation:

A supersaturated solution can be formed by dissolving solute more solute in solvent by increasing temperature of the solution. A supersaturated solution contains more quantity of solutes than can be dissolved in the solvent at room temperature. A solution may remain supersaturated until the solution has high temperature and when the temperature started lower, the extra dissolve solutes begin undissolved and remain suspended in the solution.

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-- A scientist combines 14 grams of potassium nitrate with an unknown amount of
igor_vitrenko [27]

Answer:

The unknown amount of potassium chloride is 13.6 grams.            

 

Explanation:

The reaction of 14 grams of KNO₃ with KCl produces a total mass of 27.6 grams of the products.

The law of conservation of mass tells us that the total mass of the reactants must be the same that the total mass of the products. So, we can find the mass of KCl as follows:

m_{r} = m_{p}

Where <em>r</em> is for reactants and <em>p </em>is for products

m_{KNO_{3}} + m_{KCl} = m_{p}

14 g + m_{KCl} = 27.6 g

m_{KCl} = 27.6 g - 14 g = 13.6 g

Therefore, the unknown amount of potassium chloride is 13.6 grams.           

I hope it helps you!

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Answer:

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thank me later

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