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Nutka1998 [239]
2 years ago
9

What will the cleaning sanitation and storage of food contact surfaces of equipment and utensils help prevent?

Chemistry
1 answer:
sertanlavr [38]2 years ago
4 0

Proper cleaning and sanitizing practices are critical in preventing bacteria that can cause foodborne illness.

Benefits of sanitizing:

Eliminates Pathogens.

Sanitizing Improves Home Odor.

Reduces Respiratory issues.

Decreases Allergy Flare-Ups.

Easy to Use.

Reduces Stress.

Helps the Immune System.

When and how to clean surfaces in your home.

Important to clean and sanitize kitchen premises

Cleaning your kitchen premises and equipment ensures that clean food preparation is carried out in order to improve kitchen efficiency and reduce environmental impacts.

To learn more about cleaning refer: brainly.com/question/25912875

#SPJ4

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Why does molecular polarity occur? ​
Jet001 [13]

Answer:

Water is polar because it has two unshared pairs of electrons on the central oxygen molecule. This causes the single covalent bonds between the central oxygen and both hydrogen to be pushed away. The hydrogen side of the water molecules has a positive charge and the oxygen side of the molecules has a negative charge.

6 0
3 years ago
Consider the Gibbs energies at 25 ∘C.
zysi [14]

Answer:

A)Δ​G​r​x​n​∘​=​55.7​k​J​/​m​o​l

B)Ksp=1.75×10^−10

C)Δ​G​r​x​n​∘​=​70.0​k​J​/​m​o​l

D)Ksp=5.45×10^−13

Explanation:

ΔGrxn∘=​Δ​G​f​,​p​r​o​d​u​c​t​s​∘​−​Δ​G​f​,​r​e​a​c​t​a​n​t​s​∘

To calculate for the

Ksp

of the dissolution reaction can be claculated

ΔGrxn∘=−RTlnKsp

where R is the proportionality constant equal to 8.3145 J/molK.

A)

Δ​G​r​x​n​∘​=​[​Δ​G​f​,​A​g​(​a​q​)​+​∘​+​Δ​G​f​,​C​l​(​a​q​)​−​∘​]​−​Δ​G​f​,

A​g​C​l​(​s​)​⇌​A​g​(​a​q​)​+​+​C​l​(​a​q​)​−

ΔG∘rxn=[77.1kJ/mol+(−131.2kJ/mol)]−(−109.8kJ/mol)

Δ​G​r​x​n​∘​=​55.7​k​J​/​m​o​l

b) Calculate the solubility-product constant of AgCI.

ΔGrxn∘=−RTlnKsp

55.7​k​J​/​m​o​l​=​−​(​8.3145​×​10​−​3​J​/​m​o​l​K​)​(​298.15​K)InKsp

Ksp=1.75×10^−10

c) Calculate

To calculate ΔG°rxn

for the dissolution of AgBr(s).

Δ​G​r​x​n​∘​=​[​Δ​G​f​,​A​g​(​a​q​)​+​∘​+​Δ​G​f​,​B​r​(​a​q​)​−​∘​]​−​Δ​G​f​,

Δ​G​r​x​n​∘​=​[​77.1​k​J​/​m​o​l​+​(​−​104.0​k​J​/​m​o​l​)​]​−​(​−96.90kj/mol

Δ​G​r​x​n​∘​=​70.0​k​J​/​m​o​l

d)To Calculate the solubility-product constant of AgBr.

ΔGrxn∘=−RTlnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K)lnKsp

70.0​k​J​/​m​o​l​=​−​(​8.3145​×​10​−​3​J​/​m​o​l​K​)​(​298.15​K

Ksp=5.45×10^−13

8 0
3 years ago
Element R and Element Q have the same number of valence electrons.These elements both haves similar chemical behavior, but Eleme
vovangra [49]

Answer:

This question is incomplete

Explanation:

This question is incomplete, however, element R and element Q having the same number of valence electrons means they belong to the same group in the periodic table which is the reason for there similar chemical behavior (as elements in the same group tend to have the same chemical properties).

Element R having fewer energy level (or electron shell) than element Q shows element R has fewer number of electrons than element Q and can be found earlier in the periodic table (or group in particular) when compared to element  Q

8 0
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Can someone help me with 3
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