Answer:
<em>The maximum voltage that can be applied without damaging the resistor is 4.85 V</em>
Explanation:
<u>Electric Power in a Resistor</u>
Given a resistor or resistance R connected to a circuit of voltage V carrying a current I. The relation between these three magnitudes is given by Ohm's Law:
V = R.I
The dissipated power P of a resistor can be calculated by the following equation, known as Joule's first law:

Solving the first equation for I:

Substituting in the second equation:

Simplifying:

Solving for V:

The resistor has a resistance of R=47Ω and can hold a maximum power of P=0.5 W, thus the maximum voltage is:


V = 4.85 V
The maximum voltage that can be applied without damaging the resistor is 4.85 V
B) It is turned by water to produce a direct current....... hope it helps :)
ocean waves because its not artificial
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
![v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3D%289.98%29%5E%7B2%7D-2%2A9.81%2A4.88%5C%5Cv_%7Bf%7D%5E%7B2%7D%20%3D%2099.6-95.74%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B3.8544%7D%5C%5Cv_%7Bf%7D%3D1.96%5Bm%2Fs%5D)
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.