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laila [671]
3 years ago
7

A coordinate grid is shown below: A coordinate grid from negative 2 to 0 to positive 2 is drawn. There are three grid lines betw

een a whole unit on the grid. Part A: Which point represents the origin? (2 points) Part B: Starting from the origin, explain how to plot the following three points accurately: (2, −2) (−2, 1.5) (−1, fraction 2 over 4 ) (8 points)
Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

2

Step-by-step explanation:

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Daniel [21]
Part A:

Significant level:

<span>α = 0.05

Null and alternative hypothesis:

</span><span>h0 : μ = 3 vs h1: μ ≠ 3

Test statistics:

z= \frac{\bar{x}-\mu}{\sigma/\sqrt{n}}  \\  \\ = \frac{2.78-3}{0.9/\sqrt{15}}  \\  \\ = \frac{-0.22}{0.2324} =-0.9467

P-value:

P(-0.9467) = 0.1719

Since the test is a two-tailed test, p-value = 2(0.1719) = 0.3438

Conclusion:

Since the p-value is greater than the significant level, we fail to reject the null hypothesis and conclude that there is no sufficient evidence that the true mean is different from 3.



Part B:

The power of the test is given by:

\beta=\phi\left(Z_{0.025}+ \frac{3-3.25}{0.9/\sqrt{15}}\right) -\phi\left(-Z_{0.025}+ \frac{3-3.25}{0.9/\sqrt{15}}\right) \\  \\ =\phi\left(1.96+ \frac{-0.25}{0.2324} \right)-\phi\left(-1.96+ \frac{-0.25}{0.2324} \right)=\phi(0.8842)-\phi(-3.0358) \\  \\ =0.8117-0.0012=0.8105

Therefore, the power of the test if </span><span>μ = 3.25 is 0.8105.



Part C:

</span>The <span>sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is obtained as follows:

1-0.9=\phi\left(Z_{0.025}+ \frac{3-3.75}{0.9/\sqrt{n}}\right) -\phi\left(-Z_{0.025}+ \frac{3-3.75}{0.9/\sqrt{n}}\right) \\ \\ \Rightarrow0.1=\phi\left(1.96+ \frac{-0.75}{0.9/\sqrt{n}}\right)-\phi\left(-1.96+ \frac{-0.75}{0.9/\sqrt{n}} \right) \\  \\ =\phi\left(1.96+(-3.2415)\right)-\phi\left(1.96+(-3.2415)\right) \\  \\ \Rightarrow\frac{-0.75}{0.9/\sqrt{n}}=-3.2415 \\ \\ \Rightarrow\frac{0.9}{\sqrt{n}}=\frac{-0.75}{-3.2415}=0.2314 \\  \\ \Rightarrow\sqrt{n}=\frac{0.9}{0.2314}=3.8898

\Rightarrow n=(3.8898)^2=15.13

Therefore, the </span>s<span>ample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is 16.</span>
8 0
3 years ago
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