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3 years ago

Using the following phase diagram, the area labeled A is in what phase?

1 answer:

8 0

<span>Using the following phase diagram, the area labeled A is in what phase?</span>Using the following phase diagram, the area labeled A is in the liquid phase.

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How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lo

riadik2000 [5.3K]

Answer : The energy removed must be, -67.7 kJ

Solution :

The process involved in this problem are :

$(1):C_6H_6(g)(425.0K)\rightarrow C_6H_6(g)(353.0K)\\\\(2):C_6H_6(g)(353.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(3):C_6H_6(l)(353.0K)\rightarrow C_6H_6(l)(335.0K)$

The expression used will be:

$\Delta H=[m\times c_{p,g}\times (T_{final}-T_{initial})]+m\times \Delta H_{vap}+[m\times c_{p,l}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = heat released by the reaction = ?

m = mass of benzene = 125 g

$c_{p,g}$ = specific heat of gaseous benzene = $1.06J/g^oC$

$c_{p,l}$ = specific heat of liquid benzene = $1.73J/g^oC$

$\Delta H_{vap}$ = enthalpy change for vaporization = $33.9kJ/mole=33900J/mole=\frac{33900J/mole}{78.11g/mole}J/g=434.0J/g$

Molar mass of benzene = 78.11 g/mole

Now put all the given values in the above expression, we get:

$\Delta H=[125g\times 1.06J/g.K\times (353.0-(425.0))K]+125g\times -434.0J/g+[125g\times 1.73J/g.K\times (335.0-353.0)K]$

$\Delta H=-67682.5J=-67.7kJ$

Therefore, the energy removed must be, -67.7 kJ

4 0

3 years ago

Why are thiols more nucleophilic than alcohols?

Roman55 [17]

Answer:

Thiols contain stronger acids than alcohols

Explanation:

4 0

2 years ago

Read 2 more answers

How many atoms are in the 3.5 moles of arsenic atoms?

Dmitry_Shevchenko [17]

Number of atom in one mole = 6.022 × 10²³
So, in 3.5 moles, it would be: = 6.022 × 10²³ * 3.5 = 2.1 × 10²⁴

In short, Your Answer would be 2.1 × 10²⁴ atoms

Hope this helps!

6 0

3 years ago

Read 2 more answers

P 4 + 5O 2 P 4 O 10 , 1.5 moles of product was made in 30 seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min

Airida [17]

Answer: 850.0 g/min.

Explanation:

The rate of the reaction = (ΔC/Δt) where,

ΔC is the change in concentration of reactants or products.

Δt is the change in time of the reaction proceeding.

The rate is needed to be calculated in (g/min).

We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).

mass (g) = n x molar mass,

n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.

m = 1.5 x 283.88 = 425.82 g.

ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.

The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.

<em>can be approximated to 850.0 g/min.</em>

6 0

3 years ago

Read 2 more answers

Determine the number of moles of O,(g) in the cylinder. The gram-formula mass of

FrozenT [24]

The number of mole of oxygen gas, O₂ in the cylinder given the data is 0.5 mole

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of O₂</h3>

From the question given, the following data were obtained:

Mass of O₂ = 16 g g
Molar mass of O₂ = 32 g/mol
Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 16 / 32

Mole of O₂ = 0.5 mole

Complete question

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8 0

1 year ago