Pls help thanks.....

Harrizon [31]

Well, remember we can't take the square root of a negative

so we see that we have $\sqrt{1-x^2}$
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain

b. for a TI-84, go to y-editor then input $4x \sqrt{1-x^2}$ for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7

A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7

8 0

2 years ago

Pleaseeeeeeee help me

lorasvet [3.4K]

Answer:

by my best guess, x = -5 (negative five)

Step-by-step explanation:

3 0

2 years ago

Express in a simplified exponential notation 18a^3b^2/2ab

Sauron [17]

Hey there,

The answer is: 18a^3b2/2ab=9a^2*b

:)

3 0

2 years ago

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Some college graduates employed full-time work more than hours per week, and some work fewer than hours per week. We suspect tha

Alex_Xolod [135]

Answer:

a)Null hypothesis: $\mu =40$

Alternative hypothesis: $\mu \neq 40$

b) A Type of error I is reject the hypothesis that $\mu$ is equal to 40 when is fact $\mu is equal to 40c) We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"Step-by-step explanation:Assuming this problem: "Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, [tex]\mu$ , is different from 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 43 hours and that the standard deviation is 4 hours. Based on this information, answer the questions below"

Data given

$\bar X=43$ represent the sample mean

$\mu$ population mean (variable of interest)

s=4 represent the sample standard deviation

n represent the sample size

Part a: System of hypothesis

We need to conduct a hypothesis in order to determine if actual mean is different from 40 , the system of hypothesis would be:

Null hypothesis: $\mu =40$

Alternative hypothesis: $\mu \neq 40$

Part b

In th context of this tes, what is a Type I error?

A Type of error I is reject the hypothesis that $\mu$ is equal to 40 when is fact [tex]\mu is equal to 40

Part c

Suppose that we decide not to reject the null hypothesis. What sort of error might we be making.

We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"

5 0

2 years ago

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The Percent of increase

ANEK [815]

Percent of Increase = Increase / Original * 100%

Increase = $33 - $30 = $3
Original Price = $30

Percent Increase = $3 / $30 * 100% ==== 10%

5 0

2 years ago

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