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3 years ago

1. 6:8

Mathematics

1 answer:

gtnhenbr [62]3 years ago

8 0

What are you asking? Are you asking to find an equal ratio for each?

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If g (x) = 3x²-4, then find g (-3)

Semenov [28]

Answer:

g(-3) = 23

Step-by-step explanation:

This question is telling us that x = -3. Knowing this, we can plug x into the equation and solve to find g(-3).

$g(-3) = 3(-3)^{2} -4$

$g(-3) =3(9)-4$ Square -3 to get 9

$g(-3) = 27-4$ Multiply 9 by 3 to get 27

$g(-3) = 23$ Subtract 4 from 27 to get 23

Thus, g(-3) is equal to 23.

I hope this helps! Good luck!

6 0

2 years ago

In ∆ABC, point D is the centroid. If (AE) ̅=15, (BF) ̅=27, and (CD) ̅=8, find the following lengths

Anna71 [15]

Answer:

5,18,12 cms are the answer.

Step-by-step explanation:

Given is a triangle ABC. Point D is the centroid.

E,F and G are midpoints of CB, BA and AC respectively.

AE, BF and CG are medians of the triangle.

We know that centroid divides the median in the ratio 2:1

Using this we find that AD:DE = 2:1

Or AD+DE:DE = (2+1):1

AE:DE =3:1

15:DE = 3:1 . Hence DE =5 cm.

On the similar grounds we find that DF = 1/3 BF = 9

Hence BD = DF-BF = 27-9 =18 cm

and also

CG = 3/2 times CD = 12 cm.

7 0

3 years ago

The candy of a lolipop is in the shape of a sphere with a diameter of 4 cm. The

Sever21 [200]

So so so so 0.5cm? Like

3 0

3 years ago

Saira is using the formula for the area of a circle to determine the value of LaTeX: \piπ. She is using the expression LaTeX: Ar

lord [1]

Given:

Area of a circle, A=50.265 sq. units.

Radius of circle, r = 4 units.

To find:

The value of π to the nearest thousandth.

Solution:

Formula for area of a circle is

$A=\pi r^2$

$\dfrac{A}{r^2}=\pi$

$Ar^{-2}=\pi$

Now, using $Ar^{-2}$ expression, we can find the value of π.

$\pi=50.265904(4)^{-2}$

$\pi=\dfrac{50.265904}{4^2}$

$\pi=\dfrac{50.265904}{16}$

$\pi=3.141619$

Approximate the value to the nearest thousandth (three digits after decimal).

$\pi\approx 3.142$

Therefore, the approximated value of π is 3.142.

8 0

3 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

4 0

3 years ago