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kirill115 [55]
3 years ago
12

A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. Th

e lower end of the string is suddenly displaced horizontally. How long does it take the resulting wave pulse to travel to the upper end
Physics
1 answer:
Juliette [100K]3 years ago
5 0

Answer: 0.0180701 s

Explanation:

Given the following :

Length of string (L) = 10 m

Weight of string (W) = 0.32 N

Weight attached to lower end = 1kN = 1×10^3

Using the relation:

Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

g = acceleration due to gravity = 9.8m/s^2

Weight of string = 0.32N

Time(t) = √ (0.32 * 10) / [(1*10^3) * (9.8)]

Time = √3.2 / 9800

= √0.0003265

= 0.0180701s

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Explanation:

Distance covered by the particle is given by:

Distance (d) = rate (v) × time (t)                

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2 years ago
In a 49 s interval, 595 hailstones strike a glass window of an area of 0.954 m at an angle of 25° to the window surface. Each ha
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Average  force on the window: 0.32 N

Explanation:

The average force exerted on the window is given by Newton's second law

F=\frac{\Delta p}{\Delta t}

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F=\frac{\Delta p}{\Delta t}=\frac{15.8}{49}=0.32 N

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