Since it talks about the number of particles, we would need the Avogadro's number which is an empirical value equal to 6.022×10²³ particles/mole. The other information that we have to know is the molar mass of Na₂SO₄ which is 142.04 g/mol.
Mass of a single particle of Na₂SO₄:
(142.04 grams Na₂SO₄/mol) * (1 mol/6.022×10²³ particles) = 2.359×10⁻²² g
Thus, each Na₂SO₄ weighs 2.359×10⁻²² g.
Number of Na₂SO₄ particles in the mixture:
(11.53 g Na₂SO₄) * (1 mol/142.04 g) * (6.022×10²³ particles/mol) = 4.89×10²² particles
Thus, the mixture contains 4.89×10²² particles is Na₂SO₄.
The correct procedure is:
Dissolving 45 g of NaOH in enough water to make up to 750 mL of solution
<h3>What is molarity? </h3>
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of NaOH </h3>
- Volume = 750 mL = 750 / 1000 = 0.75 L
- Molarity = 1.5 M
- Mole of NaOH =?
Mole = Molarity x Volume
Mole of NaOH = 1.5 × 0.75
Mole of NaOH = 1.125 mole
<h3>How to determine the mass of NaOH </h3>
- Mole of NaOH = 1.125 mole
- Molar mass of NaOH = 40 g/mol
- Mass of NaOH =?
Mass = mole × molar mass
Mass of NaOH = 1.125 × 40
Mass of NaOH = 45 g
Thus, to obtain 750 mL of 1.5 M NaOH solution, 45 g of NaOH will be dissolved in enough water to make up to 750 mL of solution
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As far as i know, it is nuclear fission. hope this helps.
I think it 2.25 or somethingg
1,3-cyclopentanediol has 3 possible stereoisomers. Two of which are enantiomers and are therefore, optically active, while one is optically inactive. The enantiomers are the <em>trans-</em> isomers which are (1R,3R)-1,3-Cyclopentanediol, and (1S,3S)-1,3- Cyclopentanediol.
The stereoisomer that is not optically active is the <em>cis- </em>isomer which is (1S,3R)-1,3-Cyclopentanediol and is shown in the illustration below.