G about the answer if I don’t do this I Will fail!!!!!! NO LINKS NO LYING
The uranium within these items is radioactive and should be treated with care. Uranium's most stable isotope, uranium-238, has a half-life of about 4,468,000,000 years. It decays into thorium-234 through alpha decay or decays through spontaneous fission.
Translate it to English and I would love to help u out (:
Answer:
The amount is ![x = 113.3 \ dollars](https://tex.z-dn.net/?f=x%20%20%3D%20%20113.3%20%5C%20%20dollars)
Explanation:
From the question we are told that
The distance traveled per day is ![l = 109\ km = \frac{109}{1.609} = 67.74 \ mi](https://tex.z-dn.net/?f=l%20%20%3D%20%20109%5C%20km%20%3D%20%20%5Cfrac%7B109%7D%7B1.609%7D%20%20%3D%20%2067.74%20%5C%20%20mi)
The cost of one liter is ![c = 1.10 \ euros/liter = 1.10 * 1.26 = 1.36 \ dollars/liter](https://tex.z-dn.net/?f=c%20%3D%20%201.10%20%5C%20euros%2Fliter%20%3D%201.10%20%20%2A%20%201.26%20%20%3D%201.36%20%5C%20dollars%2Fliter)
The car's gas mileage is ![b = 22.0 \ mi/gal](https://tex.z-dn.net/?f=b%20%3D%20%2022.0%20%5C%20mi%2Fgal)
Generally the amount of distance covered in one week is evaluated as
![z = 67.74 * 7](https://tex.z-dn.net/?f=z%20%3D%20%2067.74%20%2A%207)
![z = 474.18 \ mi](https://tex.z-dn.net/?f=z%20%3D%20474.18%20%5C%20%20mi)
The amount of gas used in one week by the car is mathematically represented as
![k = \frac{ z}{ b}](https://tex.z-dn.net/?f=k%20%20%3D%20%5Cfrac%7B%20z%7D%7B%20b%7D)
=> ![k = \frac{ 474.18}{ 22}](https://tex.z-dn.net/?f=k%20%20%3D%20%5Cfrac%7B%20474.18%7D%7B%2022%7D)
=> ![k = 22 \ gal](https://tex.z-dn.net/?f=k%20%20%3D%20%2022%20%5C%20gal)
converting to liters
![k = 22 * 3.78541=83.28 \ liters](https://tex.z-dn.net/?f=k%20%3D%20%2022%20%2A%20%203.78541%3D83.28%20%5C%20liters)
Thus the amount spent on gas in one week is
![x = k * c](https://tex.z-dn.net/?f=x%20%3D%20%20k%20%2A%20%20c)
=> ![x = 83.28 * 1.36](https://tex.z-dn.net/?f=x%20%20%3D%20%2083.28%20%2A%20%201.36)
=> ![x = 113.3 \ dollars](https://tex.z-dn.net/?f=x%20%20%3D%20%20113.3%20%5C%20%20dollars)
Answer:
B 1.23 g/cc
Explanation:
For something to float on seawater, the density must be less than 1.03 g/mL. If the object sinks, the density is greater than 1.03 g/mL.
Let’s examine the answer choices. Keep in mind, the ice berg is mostly below the water level.
A. 0.88 g/cc
This is less than 1.03 g/cc, which would result in floating.
B. 1.23 g/cc
This is the best answer choice. The iceberg is mostly beneath the water, but some of it is exposed. The density is greater than 1.03 g/mL, but not so much greater that it would immediately sink.
C. 0.23 g/cc
This is less than 1.03 g/cc, which would produce floating.
D. 4.14 g/cc
This is much greater than 1.03 g/cc and the result would be sinking.