The answer is C. A, B, and C would depend on what type of electron it is.
Since water does not have charged particles, water is a non-conductor. When some solutes dissolve in water they allow an electric current to flow through the water and the solution conducts electricity. These solutes are called electrolytes. ... Non-electrolytes like sugar dissolve to form molecules in solution.
2C6H14 + 19O2 ===> 12CO2 + 14H2O ... balanced equation
moled hexane present = 2.6 g x 1 mole/130 g = 0.02 moles
moles O2 present = 5.29 g x 1 mole/32 g = 0.165 moles
Which reactant is limiting? Hexane = 0.02/2 = 0.01; O2 = 0.165/19 = 0.0087
Thus O2 is limiting...
moles of H2O that can be produced =0.165 moles O2 x 14 H2O/19 CO2 = 0.122 moles H2O
Mass H2O = 0.122 moles x 18 gm/mole = 2.20 g (to 3 sig. figs.)
Answer:
Lithium and Sodium
Explanation:
Losing and electron in natural setting is characterizes of elements in group one. These are elements known as the alkaline earth metals. They are the most electropositive elements on the periodic table.
These elements ionize by losing an electron yin their outermost shell to attain the configuration of the nearest noble gas. These elements are usually found in combined and rarely seen in uncombined state principally due to their very reactive nature.
Sodium naturally would ionize by losing one electron. Other elements capable of this even at a better rate because they are more electropositive are potassium and lithium. Both are also group one alkaline metals
