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Umnica [9.8K]
2 years ago
10

NEEDS HELP REALLY QUICK PLEASE

Mathematics
1 answer:
Elis [28]2 years ago
6 0
1/3
there you go hope it helps
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3 years ago
Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

6 0
3 years ago
Two trains left Mooseport at the same time. One traveled north at 83 mph. The other traveled south at 67 mph. After how many hou
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First of all, remember if 2 people are walking away from each other at the same speed (ex 4 mph), after 1 mile, they would be 8 miles away. 4 miles south and north. So these trains go away from each other at a total of 150 mph( 67 + 83). So your equation is h = hours, 150h = 600. Divide both sides by 150 to get h = 4. 4 hours is your answer.

8 0
3 years ago
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If f(x) = 5x, what is f–1(x)?
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F=5x
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so f-1x=4x
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Six different people each brought four dishes to a gathering. Find the total number of dishes.
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The answer is 24 dishes 6x4
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2 years ago
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