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IgorC [24]
3 years ago
5

Light in vacuum travels at a speed of 3.00 x 10^8 m ^-1 s^-1 on average earth is 93,000,000 miles from the sun how many minutes

does it take sunlight to reach the earth show work please
Physics
1 answer:
NemiM [27]3 years ago
6 0
The correct unit for the speed of light is  [ m s⁻¹ ].

Time = (distance) / (speed)

Time = (9.3 x 10^7 miles) x (1609 m/mile) / (3 x 10^8 m/s) = 498.8 seconds .

That would be  <em>8.31 minutes</em>.  
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I need help with questions 6-8. Thank you!! Image is attached
Digiron [165]

6) b) 2.7 m/s

7) b) DCA

8) b) B

Explanation:

6)

In a displacement-time plot, the slope of the line is given by

m=\frac{\Delta y}{\Delta x}

where

\Delta y is the change in the y-variable, so it is the displacement

\Delta x is the change in the x-variable, so it is the time elapsed

So, the slope of the line in a displacement-time plot corresponds to the velocity:

v=m=\frac{d}{t}

Therefore, to find the velocity of the object, we have to estimate the slope of its curve.

To estimate the velocity of object B, we have to estimate the slope of the line tangent to curve B at 10 seconds.

By doing an estimate by eye, we see that the displacement of object B changes from -10 m to 0 m when time increases from about 8 s to 12 s, so the velocity is about:

v=\frac{0-(-10)}{12-8}\sim 2.5 m/s

So the closest option is b) 2.7 m/s.

7)

As we said in part A, the velocity of each object is given by the slope of each curve.

Therefore:

- The steeper the curve, the higher the velocity

- The less steep the curve, the lower the velocity

From the graph, we observe that, among A, C and D:

- Curve D has the largest slope (in absolute value), so object D has the largest magnitude of the velocity

- Curve C is less steep than curve C, so object C has the second largest magnitude of velocity

- Curve A is flat, so the slope is zero, so its velocity is zero

So, from greatest magnitude to lowest magnitude of velocity, we have:

b) DCA

8)

In the graph, the overall displacement of each object is given by the change in the y-variable, \Delta y.

This means that the object with largest displacement is the object whose curve has the largest variation in y.

From the graph, we see that:

- Object b has the largest variation in y,  from -15 m to 30 m, so

\Delta y=30-(-15)=45 m

- Then, object D has the second largest displacement (in magnitude), from -15 m to 25 m,

|\Delta y| = 25 -(-15)=40 m

Finally, object C has displacement

\Delta y = 20-(-5)=25 m

While object A has displacement zero. Therefore, the correct option is

b) B

3 0
3 years ago
Convertir 500 f a grado celsios
Allushta [10]

Answer:

260° C

Explanation:

si

5 0
2 years ago
Read 2 more answers
An object is initially moving at an unknown velocity. It accelerates at a rate of 1.5m/s2 to a new velocity of 60 m/s in 25 s. W
Alexandra [31]
<h3>Answer:  22.5 m/s</h3>

=====================================================

Work Shown:

acceleration = ( finalVelocity - initialVelocity )/(change in time)

1.5 = (60 - x)/(25)

1.5*25 = 60-x

37.5 = 60-x

x = 60-37.5

x = 22.5

The initial velocity is 22.5 m/s

6 0
3 years ago
Which of the following is NOT a valid reason that less energy is transferred at each level of the food chain?
stealth61 [152]

Answer:

B.

Explanation:

I'm pretty sure the answer is B because animals at the top need a lot of energy, so to make up for loss of energy at the higher levels, those organisms at the top have to consume a lot more.

5 0
2 years ago
A parallel plate capacitor is charged by connecting it to a battery. After the steady state is reached, the electric energy stor
Vladimir79 [104]

Answer: C. The amount of work needed to charge the capacitor is UE, because when integrating the equation W = integral qdV with the correct limits yield the equation for the energy stored on a capacitor, UE = 1/2qV.

Explanation:

The claim about the amount of work that is needed to charge the capacitor and give evidence to support this claim is option C "The amount of work needed to charge the capacitor is UE, because when integrating the equation W = integral qdV with the correct limits yield the equation for the energy stored on a capacitor, UE = 1/2qV".

Option C is the correct answer because when we a capacitor is being charged, the amount of work that's being stored as a potential energy.

3 0
2 years ago
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