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Bad White [126]
3 years ago
13

6x+7y=4x+4y Complete the missing value in the solution to the equation

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

Step-by-step explanation:

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Which statements are true about exponential functions? Check all that apply.
babunello [35]
The following statements are true about exponential functions:
-The domain is all real numbers.
- The input to an exponential function is the exponent.
- The base represents the multiplicative rate of change.

The reason why the other two options are wrong are explained below:
The range of exponential functions is not always includes negative numbers; on the contrary, the range is the set of all positive real numbers.

The graph of an exponential function does not have a horizontal asymptote at x = 0; contrarily, the equation of the horizontal asymptote of the graph of is y = 0, which is the x-axis.
8 0
3 years ago
Read 2 more answers
Simplify the product
Lostsunrise [7]

How to get answer:

((-2a^2)(b))(9a^5b^3-4ab^5)

=((-2a^2)(b))(9a^5b^3+-4ab^5)

=((-2a^2)(b))(9a^5b^3)+((-2a^2)(b))(-4ab^5)

Answer: =-18a^7b^4+8a^3b^6

7 0
3 years ago
An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
Ira Lisetskai [31]

Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


4 0
3 years ago
Read 2 more answers
Given the graph below, which of the following statements is true?
Elza [17]

Answer:

Option d is right

Step-by-step explanation:

A function is called one to one if two x will not have same y value.

In other words, in the domain each x is matched with a unique y and if x1 not equals x2 we have the corresponding y1 will not be equal to y2.

In the graph given, we find that the y value say 1 has preimages in both to the right of y axis and to the left of y axis.

Hence this is not one to one.

This is a function because each x has a unique image. If we draw a vertical line in any part of the graph we find that it  cuts only one time the graph of f(x)

Hence f is a function but not one to one.  A one to one function need not pass through the origin.

Hence we find that of the options given, a,b and c are wrong.

But option d is right.

7 0
3 years ago
a fruit company delivers its fruit in two types of boxes large and small a delivery of five large boxes and two small boxes have
hodyreva [135]

Answer:

Large boxes:19 kg

Small boxes:5 kg

8 0
3 years ago
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