Answer:
The correct option is (B)
Explanation:
The square of wave function or probability density shows the probability of finding the particle at a given position and time. It can be given as :
![P(x)\ dx=\psi *(x,t)\psi (x,t)\ dx](https://tex.z-dn.net/?f=P%28x%29%5C%20dx%3D%5Cpsi%20%2A%28x%2Ct%29%5Cpsi%20%28x%2Ct%29%5C%20dx)
By finding the square of wave function, we can find the location of the particle statistically. Hence, the correct option is (B) "The square of the wave function represents the probability of finding the particle at a given position and time".
Along with neurons, the nervous system contains other specialized cells called glial cells (or simply glia), which provide structural and metabolic support. Nervous systems are found in most multicellular animals, but vary greatly in complexity.
If you or any else needs the answer for this it is C. +1.11 m/s.
Answer:
a) When R is very small R << r, therefore the term R+ r will equal r and the current becomes
b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes
Explanation:
<u>Solution :</u>
(a) We want to get the consumed power P when R is very small. The resistor in the circuit consumed the power from this battery. In this case, the current I is leaving the source at the higher-potential terminal and the energy is being delivered to the external circuit where the rate (power) of this transfer is given by equation in the next form
P=∈*I-I^2*r (1)
Where the term ∈*I is the rate at which work is done by the battery and the term I^2*r is the rate at which electrical energy is dissipated in the internal resistance of the battery. The current in the circuit depends on the internal resistance r and we can apply equation to get the current by
I=∈/R+r (2)
When R is very small R << r, therefore the term R+ r will equal r and the current becomes
I= ∈/r
Now let us plug this expression of I into equation (1) to get the consumed power
P=∈*I-I^2*r
=I(∈-I*r)
=0
The consumed power when R is very small is zero
(b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes
I=∈/R
The dissipated power due toll could be calculated by using equation.
P=I^2*r (3)
Now let us plug the expression of I into equation (3) to get P
P=I^2*R=(∈/R)^2*R
=∈^2/R