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Reptile [31]
3 years ago
15

Determine the number of water molecules in 115g of chromium(III) oxalate trihydrate.

Chemistry
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

4.92x10^{23}molecules H_2O

Explanation:

Hello,

In this case, since the chromium(III) oxalate trihydrate is Cr₂(C₂O₄)₃ ·3H₂O whose molar mass is 422 g/mol and one mole of chromium(III) oxalate trihydrate contains three moles of water, by also considering that one mole of substance contains the Avogadro´s number in particles, the number of water molecules turns out:

=115gCr_2(C_2O_4)_3\ 3H_2O*\frac{1molCr_2(C_2O_4)_3\ 3H_2O}{422gCr_2(C_2O_4)_3\ 3H_2O}*\frac{3molH_2O}{1molCr_2(C_2O_4)_3\ 3H_2O}  *\frac{6.022x10^{23}molecules H_2O}{1molH_2O} \\\\=4.92x10^{23}molecules H_2O

Best regards.

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