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3 years ago

Need help on this ASAP !!!!

Chemistry

1 answer:

JulijaS [17]3 years ago

3 0

Answer:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.

Explanation:

To balance the equation, you should apply the law of conservation of mass for the equations.

The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).

Hydrocarbon is burned in oxygen to produce CO₂ and H₂O.

So, the given equation is balanced as:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.

that 1.0 mole of C₃H₈ is burned in 5.0 moles of O₂ to produce 3.0 moles of CO₂ and 4.0 moles of H₂O.

The no. of all atoms is the same in both of reactants and products side.

C (3), O (10), and H (8).

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Calculate the volume of 1M NaOH required to neutralize 200 cc of 2M HCI. What mass of sodium

Nezavi [6.7K]

NaOH+HCl-> NaCl+H2O

1 mole of NaOH

1 mole of HCl.

To calculate volume of NaOH

CaVa/CbVb= Na/Nb

Where Ca=2M

Cb=1M

Va=200cm³

Vb=xcm³

Substitute into the equation.

2×200/1×Vb=1/1

400/Vb=1/1

Cross multiply

Vb×1=400×1

Vb=400cm³

To calculate the mass of sodium chloride, NaCl from the neutralization rxn.

Mole of NaCl=1

Molar mass of NaCl= 23+35.5=58.5

Mass=xgrammes.

Mass of NaCl=Number of moles × Molar mass.

Substitute

Mass of NaCl= 1×58.5

=58.5g

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. The compound Fe(NO3)3(s) is classified as a(n):?. a. polyatomic compound. b. molecular compound. c. ionic compound. d. multi-a

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Whats the pure substance that cannot be separated into any other substances

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How many particles are present in 12.47 grams of NaCl

liq [111]

Answer:

1.26*10²³ particles are present in 12.47 grams of NaCl

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

So, first of all you must know the amount of moles that represent 12.47 grams of NaCl. For that it is necessary to know the molar mass.

You know:

Na: 23 g/mole
Cl: 35.45 g/mole

So the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole

Now you apply a rule of three as follows: if 58.45 grams are present in 1 mole of NaCl, 12.47 grams in how many moles will they be?

$moles=\frac{12.47 grams*1 mole}{58.45 grams}$

moles= 0.21

You apply a rule of three again, knowing Avogadro's number: if in 1 mole of NaCl there are 6,023 * 10²³ particles, in 0.21 moles how many particles are there?

$number of particles=\frac{0.21 moles*6.023*10^{23} }{1 mole}$

number of particles= 1.26*10²³

1.26*10²³ particles are present in 12.47 grams of NaCl

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3 years ago