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bekas [8.4K]
4 years ago
6

What is the density of a 21.0 g object if, when added to a graduated cylinder, it makes the water level rise from 25.00 mL to 28

.50 mL? *
Chemistry
1 answer:
polet [3.4K]3 years ago
4 0
D=m/v
density = 21/3.5
density = 6 g/ml
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Oxygen is a chemical element with symbol O and atomic number 8. Classified as a nonmetal, Oxygen is a gas at room temperature.

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Which of the following is an organic compound? carbon monoxide (CO) sodium chloride (NaCl) sulfur oxide (SO) water (H2O)
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The answer should be water (H2O)


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When 8.21 l of c3h8 (g) burn in oxygen, how many liters of oxygen are consumed? all gas volumes are measured at the same tempera
just olya [345]
<span>8.21 L of C3H8(g) Lets take c as the molar volume at that temperature.
    c L <><> 5c L
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5 0
3 years ago
Classify the reaction by their type. Note there may be more than one way to classify a reaction.
Nadya [2.5K]

Answer:

Redox reaction and single displacement

Explanation:

This reaction is first of all a redox reaction. A redox reaction is a reaction that involves both oxidation and reduction. Oxidation involves increase in oxidation number while reduction involves decrease in oxidation number.

Copper (Cu) had an oxidation number of "0" as a reactant but had an oxidation number of "2+" in the product [Cu(NO₃)₂] hence oxidation occurred.

Nitrogen (N) had an oxidation number of "5+" in the reactant (HNO₃) but had an oxidation number of "4+" in the product (NO₂) hence reduction also occurred.

Also, from the reaction, it can be deduced that copper (Cu) displaced hydrogen (H) from the nitric acid (HNO₃) solution to form copper (II) nitrate [Cu(NO₃)₂]. It should be noted that copper can displace hydrogen because it is higher than hydrogen in the electrochemical series. Hence, this reaction can also be called a single displacement reaction. A single displacement reaction is a reaction in which an atom of an element replaces another atom in a compound (as seen in the equation given in the question).

3 0
3 years ago
How many moles are in 2.8x10^24 atoms of silicon?
sergejj [24]

Answer:

4.6 mol Si

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 2.8 × 10²⁴ atoms Si

[Solve] moles Si

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                   \displaystyle 2.8 \cdot 10^{24} \ atoms \ Si(\frac{1 \ mol \ Si}{6.022 \cdot 10^{23} \ atoms \ Si})
  2. [DA] Divide [Cancel like units]:                                                                        \displaystyle 4.64962 \ mol \ Si

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

4.64962 mol Si ≈ 4.6 mol Si

6 0
3 years ago
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