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Usimov [2.4K]
3 years ago
13

Please help it's Chemistry​

Chemistry
1 answer:
dsp733 years ago
7 0

Answer:nothing beats the chemistry between us :) smooth right?

Explanation:I’m pretty sure u have to show the part before the questions so that people can respond to it since there is no info on how to answer the question :p

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I WILL MARK BRAINLISET FOR WHOEVER GETS THIS RIGHT! A pot is placed on a gas flame, and the water inside the pot begins to boil.
NNADVOKAT [17]

Answer:

B.     Warm water rises within the pot.?

Explanation

<em>There wasn't enough information given for me to safely determine the correct answer.</em>

8 0
3 years ago
I need help with this question ​
VARVARA [1.3K]

Answer:

2.25×10¯³ mm.

Explanation:

From the question given above, we obtained the following information:

Diameter in micrometer = 2.25 μm

Diameter in millimetre (mm) =?

Next we shall convert 2.25 μm to metre (m). This can be obtained as follow:

1 μm = 1×10¯⁶ m

Therefore,

2.25 μm = 2.25 μm / 1 μm × 1×10¯⁶ m

2.25 μm = 2.25×10¯⁶ m

Finally, we shall convert 2.25×10¯⁶ m to millimetre (mm) as follow:

1 m = 1000 mm

Therefore,

2.25×10¯⁶ m = 2.25×10¯⁶ m /1 m × 1000 mm

2.25×10¯⁶ m = 2.25×10¯³ mm

Therefore, 2.25 μm is equivalent to 2.25×10¯³ mm.

6 0
3 years ago
Which of the temperatures below is most likely to be the boiling point of water at 880 torr?view available hint(s)which of the t
Luden [163]
Boiling point<span>  is the </span>temperature<span> at which the vapor pressure of the liquid equals the surrounding pressure.

Above boiling point point, liquid get converted into vapour.

Now, boiling point of water is 100 oC at room pressure. Room pressure is equal to 760 torr. Thus, at 100 oC, vapour pressure of water becomes equal to 760 torr.

Now, if external pressure is increased to 880 torr, more heat is to be supplied so that vapour pressure of water equals 880 torr.

So, at 880 torr, boiling point of water will be more than 100 oC. In present case, most like the boiling point of water is equal to 105 oC.


</span>
6 0
3 years ago
Heat is added to a 200.-gram sample of H2O(s) to melt the sample at 0°C. Then the resulting H2O (image) is heated to a final tem
pochemuha
You are given 200 grams of H2O(s) at an initial temperature of 0°C. you are also given the final temperature of water after heating at 65°C. You are required to get the total amount of heat to melt the sample. The specific heat capacity, cp, of water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for heat, Q, is  

Q = m(cp)(T2-T1)
Q = 200g(4.186 J/g-°C )(65°C - 0°C)
<u>Q = 54,418J</u>
3 0
3 years ago
Read 2 more answers
What is the pH of a neutral solution at 25°C?<br> 7<br> 1
Kaylis [27]

Answer:

I pretty sure it's the pH level 7

8 0
3 years ago
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