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Fed [463]
3 years ago
5

Please help me please

Chemistry
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

Explanation:

Molarity = moles / volume (L)

moles = mass (g) / Molecular weight (g/mol)

so you have mass in gram and volume in ml ( Volume must be in litter because unit of mass is gram )

g = L     ,   mg = ml

first you must calculate the number of moles for each molecule and convert the ml to L and use the molarity law to calculate molarity for each molecule .

Ex71.

a.   Mw for NaCl = 23+35 = 58 g/mole

no of moles = 1.5 / 58 = 0.025

ml to L = 100/1000 = 0.1 L

Molarity = 0.025 / 0.1 = 0.25 M

b. Mw for K2CrO4 = 39x2 + 52 + 16x4 = 194 g/mol

no of moles = 1.5 / 194 = 0.0077

ml to L = 100 / 1000 = 0.1 L

Molarity = 0.0077 / 0.1 = 0.077 M

----------------------------------------------

Ex 72

a.  Mw for MgBr = 24 + 80 = 104 g/mol

no of moles = 20 / 104 = 0.19

ml to L = 250 / 1000 = 0.25 L

Molarity = 0.19 / 0.25 = 0.76 M

b. Mw for LiCO = 7 + 12 + 16 = 35 g/mol

no of moles = 5.55 / 35 = 0.158 moles

ml to L = 75 / 1000 = 0.075 L

Molarity = 0.158 / 0.075 = 2.106 M

Good Luck

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3 0
4 years ago
What is the most mass of (NH4)2CO3 (H=1,C=12,N=14,O=16
Agata [3.3K]

Answer:

96.09 g/mol

Explanation:

You just need to first get the atomic weights of the elements involved. You can easily get these from your periodic table.

If you are going to do this properly, please use the weight with at least two decimal places for accuracy (e.g. 15.99 g/mol).

Also, please take note that I will be using the unit g/mol for all the weights. Thus,

Step 1

N = 14.01 g/mol

H = 1.008 g/mol

O = 16.00 g/mol

C = 12.01 g/mol

Since your compound is  

(

N

H

4

)

2

C

O

3

, you need to multiply the atomic weights by their subscripts. Therefore,

Step 2

N = 14.01 g/mol × 2 =

28.02 g/mol

H = 1.008 g/mol × (4×2) =

8.064 g/mol

 

O = 16.00 g/mol × 3 =

48.00 g/mol

C = 12.01 g/mol × 1 =

12.00 g/mol

To get the mass of the substance, we need to add all the weights from Step 2.

Step 3

molar mass of

(

NH

4

)

2

CO

3

=

(28.02 + 8.064 + 48.00 + 12.01) g/mol

=

96.09 g/mol

this is a google search and a example i hope is helps to solve

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3 years ago
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