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melomori [17]
3 years ago
11

How does the presence of a nucleus provide a method of basic cell classification?

Chemistry
1 answer:
Zanzabum3 years ago
7 0

Answer:

Sample Respond: The nucleus maintains the integrity of genes and controls the activities of the cell by regulating gene expression—the nucleus is, therefore, the control center of the cell.

good luck

Explanation:

I got 100 mark as brainiest

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An object weighs 32 newtons. What is its mass if a gravitometer indicates that g = 8.25 m/sec2?
lys-0071 [83]

Answer:

3.88kg

Explanation:

weight=mass_of_body(m) x acceleration_due_to_gravity(g)

The weight is given and acceleration is also give

For mass divide the weight by acceleration.

5 0
2 years ago
Why do cars tires need more air in the winter then in the summer?
Anastaziya [24]
<span>D) Temperature is lower so the air inside the tires contracts

In cold, we all know temperature is lower, and we know, it reduces the movement of air, so it contracts

Hope this helps!</span>
5 0
3 years ago
Answer 23 please....
marishachu [46]
The answer is 10. Each capital letter is an atom. The tiny numbers represent how many atoms of that type
7 0
3 years ago
Using the nernst equation calculate the cell voltage for: fe(s) + cd2+(aq) â fe2+(aq) + cd(s) when the [fe2+] = 0.10 m and [cd2+
Oksi-84 [34.3K]
The Nernst equation is:

E = E° - RTlnK/nF
where
E° is the standard potential voltage
R is the universal gas constant = 8.314 J/mol·K
K is the reaction quotient
n is the number of moles electrons transferred
F is Faraday's constant = 96,500 C/mol e⁻

Let's determine K first. The overall reaction is:

Fe(s) + Cd²⁺(aq) --> Fe²⁺(aq) + Cd(s)
Accounting for aqueous phases only, 
K = [products]/[reactants] = [Fe²⁺]/[Cd²⁺] = 0.10 M/1.4 M = 1/14

From the reactions written, you can see that 2 electrons were transferred. So, n = 2.

Lastly, the value for E⁰ is the sum of individual E⁰ of the reactions.
E⁰ = E⁰cathode - E⁰anode
Cathode reaction: Fe(s) --> 2e + Fe²⁺ (E⁰cathode = 0.44 V)
Anode reaction: Cd²⁺ + 2e --> Cd(s) (E⁰anode = -0.4 V)
Thus,
E⁰ = 0.44 - -0.4 = 0.84 V

Substituting the values (assume T at room temperature = 298 K),
E = 0.84 - (8.314)(298 K)(ln 1/14)/(2)(96,500)
<em>E = 0.87 V</em>
5 0
4 years ago
Correct possible values of l for n = 4?
Kamila [148]

Answer:

0,1,2,3

Explanation:

for the given value of n , l = 0 to n-1

so if n = 4

l = 0 to 4-1

6 0
3 years ago
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