Falling objects drop with an average acceleration of -9.8 m/s2. If an object falls from rest from a tall building, how long will
1 answer:
Answer:
It will take t = 5 [s]
Explanation:
To solve this problem we must use the following equation of kinematics, it is important to make it clear that when the object is dropped, its initial velocity is zero.
Let's take all the signs of the equation as positive, since the object falls in the direction of motion.
where:
Vf = final velocity = 49 [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
49 = 0 + 9.81*t
t = 49/9.81
t = 5 [s]
You might be interested in
Answer:
<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>
Explanation:
<u>Free Fall Motion </u>
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:
y = 2.54 m
The final speed is computed below:
vf = 7.06 m/s
The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s
Answer:
The magnitude of the applied force is 94.74 N
Explanation:
Mass of the block, m = 11 kg
Angle of inclination of the plane,
Friction coefficient,
Now,
Normal force that acts on the block is given by:
(1)
Now, to maintain the equilibrium parallel to ramp the forces must be balanced.
Thus
(2)
From eqn (1) and (2)
F = 94.74 N