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Neko [114]
3 years ago
6

Falling objects drop with an average acceleration of -9.8 m/s2. If an object falls from rest from a tall building, how long will

it take before it reaches a speed of -49 m/s?
Physics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

It will take t = 5 [s]

Explanation:

To solve this problem we must use the following equation of kinematics, it is important to make it clear that when the object is dropped, its initial velocity is zero.

Let's take all the signs of the equation as positive, since the object falls in the direction of motion.

v_{f} =v_{o} +(g*t)

where:

Vf = final velocity = 49 [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

49 = 0 + 9.81*t

t = 49/9.81

t = 5 [s]

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melisa1 [442]
Weight can be explained as the force with which the gravity pulls an object. Your weight will not be the same in all planets. In moon, you will weigh far lesser than how much you weigh on the earth. However, in earth and in the moon, your mass will remain the same.
6 0
3 years ago
A grapefruit falls from a tree and hits the ground 0.72 s later.
xxTIMURxx [149]

Answer:

<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>

Explanation:

<u>Free Fall Motion </u>

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

\displaystyle y=\frac{gt^2}{2}

Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:

\displaystyle y=\frac{9.8\cdot 0.72^2}{2}

y = 2.54 m

The final speed is computed below:

vf=9.8\cdot 0.72

vf = 7.06 m/s

The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s

6 0
3 years ago
Which of these statements best describes the difference between electromagnetic and gravitational forces in the solar system?
kodGreya [7K]
It's B-<span>Electromagnetic forces are stronger than gravitational forces</span>
5 0
3 years ago
Read 2 more answers
A 11kg block slides up a 30° inclined plane at a constant velocity. The coefficient of friction between the block and the plane
astra-53 [7]

Answer:

The magnitude of the applied force is 94.74 N

Explanation:

Mass of the block, m = 11 kg

Angle of inclination of the plane, \theta = 30^{\circ}

Friction coefficient, \mu_{k} = 0.2

Now,

Normal force that acts on the block is given by:

F_{N} = mgcos\theta + Fsin\theta           (1)

Now, to maintain the equilibrium parallel to ramp the forces must be balanced.

Thus

Fcos\theta = \mu_{k}F_{N}                       (2)

From eqn (1) and (2)

Fcos\theta = \mu_{k}(mgcos\theta + Fsin\theta)

F(cos\theta - \mu_{k}sin\theta) = \mu_{k}mgcos\theta

F = \frac{\mu_{k}mgcos\theta}{cos\theta - \mu_{k}sin\theta}

F = \frac{0.2\times 11\times 9.8cos30^{\circ}}{cos30^{\circ} - 0.2\times sin30^{\circ}}

F = 94.74 N

3 0
4 years ago
You stand on a bridge above a river and drop a rock into the water below from a height of 35m (assume no air resistance)
Katyanochek1 [597]

Answer:

Free fall time t:

2.6717061011357 sec

Free fall velocity v:

26.200486636702 m/s    

= 94.321751892127    km/h    

Explanation:

6 0
3 years ago
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