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Usimov [2.4K]
3 years ago
5

Brainiest plsss helpp

Chemistry
2 answers:
ddd [48]3 years ago
6 0

Answer:

A) 19230 kg/ m3

Explanation:

divided it's mass by its volume ti get it's density

500/0.026 = 19230

svlad2 [7]3 years ago
3 0

Answer:

\boxed {\boxed {\sf  A. \ 19,320 \ kg/m^3}}

Explanation:

We want to find the density. The formula is mass over volume.

\rho = \frac{m}{v}

The mass is 500 kilograms. The volume is 0.026 cubic meters.

m= 500 \ kg \\v=0.026 \ m^3

Substitute the values into the formula.

\rho= \frac{ 500 \ kg}{ 0.026 \ m^3}

Divide.

\rho = 19230.7692 \ kg/m^3

This is just about equal to 19,320 kg/m³, so choice A is correct.

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Why would a scientist want to replicate another scientist's experiment?
choli [55]

Answer:

See the answer below

Explanation:

<u>A scientist B might want to replicate the experiment of another scientist A in order to assess the claims made by scientist A.</u> In other words, replication of the experiment of another scientist is done to see if a similar outcome would be arrived at or there would be variations.

<em>The claims made by a scientist while reporting the outcome of a particular experiment must be reproducible by another scientist under similar conditions. Otherwise, the claims are said to be false.</em>

7 0
3 years ago
Which metal will lose electrons more easily, Ca or Mg?
alisha [4.7K]
Yes it is not or it will
3 0
3 years ago
Can someone please help I need help?!?!
anzhelika [568]

Answer:

a: 6 moles

b: 6.75 moles

c: 5 grams

Explanation:

a: mole ratio 2:3

b: mole ratio 2:3

c: mole ratio 2:2

7 0
3 years ago
How much energy (in Joules) is required to convert 129 grams of ice at −23.0 °C to liquid water at 18.0 °C?
Karo-lina-s [1.5K]

Answer:

The energy that is required for the process is:

6230.7 J + 42957 J + 9715.2 J = <u>58902.9 joules</u>

Explanation:

This is a calorimetry problem:

Q = m . C . ΔT

Q = heat; m = mas; C is the specific heat and

ΔT = Final T° - Initial T°

Q = C lat . m

Q = Heat

m = mass

C lar = Latent heat of fusion

First of all we calculate the heat for ice, before it takes the melting point. (from -23°C  to 0°C)

Q = 129 g . 2.10 J/g°C . (0°C - (-23°C)

Q = 129 g . 2.10 J/g°C . 23°C → 6230.7 joules

Then, the ice has melted. To be melted and change the state it required:

Q = C lat . m

Q = 333 J/°C . 129 g → 42957 joules

And in the end, we have water that changed its T° from O°C to 18°C

Q = 129 g . 4.184 J/g °C . (18°C - 0°C)

Q = 9715.2 Joules

The energy that is required for the process is:

6230.7 J + 42957 J + 9715.2 J = 58902.9 joules

5 0
3 years ago
How many milliliters of a 3.0 M HCL solution are required to make 250.0 milliliters of 1.2 M HCL
tiny-mole [99]
You can use M x V = M' x V'

3 x V = 250 x 1.2

V = 100 ml
5 0
3 years ago
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