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Usimov [2.4K]
3 years ago
5

Brainiest plsss helpp

Chemistry
2 answers:
ddd [48]3 years ago
6 0

Answer:

A) 19230 kg/ m3

Explanation:

divided it's mass by its volume ti get it's density

500/0.026 = 19230

svlad2 [7]3 years ago
3 0

Answer:

\boxed {\boxed {\sf  A. \ 19,320 \ kg/m^3}}

Explanation:

We want to find the density. The formula is mass over volume.

\rho = \frac{m}{v}

The mass is 500 kilograms. The volume is 0.026 cubic meters.

m= 500 \ kg \\v=0.026 \ m^3

Substitute the values into the formula.

\rho= \frac{ 500 \ kg}{ 0.026 \ m^3}

Divide.

\rho = 19230.7692 \ kg/m^3

This is just about equal to 19,320 kg/m³, so choice A is correct.

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The volume occupied by the gas in the container is 1 m³

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Where P₁ = 200kpa

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if its initial volume is 1.5

then,

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200 × 1.5 = 300 × V₂

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Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

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3 years ago
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