Question

At STP, 32 grams of O2 would occupy the same volume as:

Answer 1

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

Further explanation

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

• 4.0 g of He
• 8.0 g of CH₄
• 64 g of H₂
• 32 g of SO₂

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

$\tt \dfrac{32}{32}=1$

• He

$\tt mol=\dfrac{4}{4}=1$

• CH₄

$\tt mol=\dfrac{8}{16}=0.5$

• H₂

$\tt mol=\dfrac{64}{2}=32$

• SO₂

$\tt mol=\dfrac{32}{64}=0.5$

So mol of 4 g He = mol of 32 g O₂