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enot [183]
3 years ago
6

At STP, 32 grams of O2 would occupy the same volume as:

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
4 0

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

<h3>Further explanation</h3>

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

  • 4.0 g of He
  • 8.0 g of CH₄
  • 64 g of H₂
  • 32 g of SO₂

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

\tt \dfrac{32}{32}=1

  • He

\tt mol=\dfrac{4}{4}=1

  • CH₄

\tt mol=\dfrac{8}{16}=0.5

  • H₂

\tt mol=\dfrac{64}{2}=32

  • SO₂

\tt mol=\dfrac{32}{64}=0.5

<em>So mol of 4 g He = mol of 32 g O₂</em>

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