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11Alexandr11 [23.1K]
3 years ago
12

A soccer ball is kicked horizontally and rolled off of a 30 meter high cliff. The soccer ball was kicked with a velocity of 17m/

s. How long did it take before the ball hit the ground? How far from the cliff did the ball land? (Make sure to include units.)
VERTICLE
Acceleration =
Distance =
Initial velocity=
Time=
HORIZONTAL
Distance=
Velocity=
Time=
Show your work when solving for time:


Show your work when solving for horizontal distance:
Physics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:This will hopefully help. It took me a while so will you mark me brainliest? Thanks!

Explanation:

velocity=Vertical (y) info:

• y = -22.0 m

• viy = 0 m/s

• ay = -9.8 m/s2

distance=

acceleration=

time=

horizontal=Horizontal (x) info:

• x = 35 m

• vix = ?

• ax = 0 m/s2

Initial velocity=16.5 m/s

VOCAB:Horizontal motion is constant

velocity- motion

acceleration-increase in the rate or speed of something.

distance-Distance is a numerical measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria (e.g. "two counties over"). The distance from a point A to a point B is sometimes denoted as. .

time-a point of time as measured in hours and minutes past midnight or noon.

Explanation:

The soccer ball travels a horizontal distance of

33.9 m after being kicked with horizontal velocity of 18.8ms−1. Assuming air resistance is negligible.

Time of flight of the ball

t=Distance Speed=33.918.8s In the vertical direction kinematic equation is

height

h=ut+12gt2 Initial velocity uv=0, acceleration due to gravity g=9.81ms−2. Inserting various values we get h=0×33.918.8+12×9.81×(33.918.8)2⇒h=12×9.81×(33.918.8)2

⇒h=15.9m, rounded to 3 sig. figs

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A 3.0 kg object is loaded into a toy spring gun, and the spring has a spring constant 750N/m. The object compresses the spring b
kiruha [24]

Answer:

Explanation:

mass of object, m = 3 kg

spring constant, K = 750 n/m

compression, x = 8 cm = 0.08 m

angle of gun, θ = 30°

(a) As the ball is launched, it has some velocity due to the compression in the spring, so it has some kinetic energy.

(b) Let v be th evelocity of ball at the tim eof launch.

by using the conservation of energy

1/2 Kx² = 1/2 mv²

750 x 0.08 x 0.08 = 3 x v²

v = 1.265 m/s

By use of the formula of maximum height

h = \frac{v^{2}Sin^{2}\theta}{2g}

h = \frac{1.265^{2}Sin^{2}30}{2\times 9.8}

h = 0.02 m

h = 2 cm  

4 0
3 years ago
What is necessary to designate a position? A. a reference point B. a direction C. fundamental units D. motion E. all of these
max2010maxim [7]

Answer:

E. all of these

Explanation:

The designation of a point in space all the points that necessary

- reference point

- a direction

- fundamental units

- a direction

- motion

all are necessary to designate a point in space. Hence option E is correct.

For example in simple harmonic motion we need to specify all the above factors of the object in order to designate the position of the object.  

8 0
3 years ago
A stone is dropped from the upper observation deck of a tower, "500" m above the ground. (Assume g = 9.8 m/s2.) (a) Find the dis
Yuri [45]

Answer:

h₍₁₎ = 495,1 meters

h₍₂₎ = 480,4 m

h₍₃₎ = 455,9 m

...

..

Explanation:

The exercise is "free fall". t = \sqrt{\frac{2h}{g} }

Solving with this formula you find the time it takes for the stone to reach the ground (T) = 102,04 s

The heights (h) according to his time (t) are found according to the formula:

h(t) = 500 - 1/2 * g * t²

Remplacing "t" with the desired time.

4 0
3 years ago
A truck traveling with an initial velocity of 22m/s comes to a stop in 17.32 secs. What is the acceleration of the truck?
Tomtit [17]

Explanation:

Given:

v₀ = 22 m/s

v = 0 m/s

t = 17.32 s

Find: a

v = at + v₀

(0 m/s) = a (17.32 s) + (22 m/s)

a = -1.270 m/s²

Round as needed.

6 0
2 years ago
Read 2 more answers
A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative r
sergij07 [2.7K]

Answer:

The workdone is  W = 1.712 *10^{-20 } \  J  

Explanation:

From the question we are told that

    The potential difference is  V  =  107 mV =  107 *10^{-3} \  V

Generally the charge on  Na^{+} is  Q_{Na^{+}} = 1.60 *10^{-19 } \  C

 Generally the workdone is mathematically represented as

         W =  Q_{Na^{+}}V

=>     W = 1.60 *10^{-19 } *  107 *10^{-3}    

=>     W = 1.712 *10^{-20 } \  J    

8 0
3 years ago
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