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3 years ago

Which molecule contains the smallest number of hydrogen atoms? A) N2H4. B) Al(OH) 3. C) (NH4) 2SO4. D) NH4NO3.

Chemistry

2 answers:

Vesna [10]3 years ago

7 0

The molecule that contains the fewest number of Hydrogen atoms would be B. Al(OH)3. It only has 3 Hydrogen atoms.

Svetach [21]3 years ago

3 0

Answer: Option (B) is the correct answer.

Explanation:

In a molecule of $N_{2}H_{4}$ , there are 2 nitrogen atoms and 4 hydrogen atoms.

In a molecule of $Al(OH)_{3}$ , there are one aluminium atom, three oxygen atoms, and three hydrogen atoms.

In a molecule of $(NH_{4})_{2}SO_{4}$ , there are 2 nitrogen atoms, 8 hydrogen atoms, one sulfur atom and 4 oxygen atoms.

In a molecule of $NH_{4}NO_{3}$ , there are 2 nitrogen atoms, 4 hydrogen atoms and 3 oxygen atoms.

Therefore, we can conclude that out of the given options $Al(OH)_{3}$ is the molecule which contains the smallest number of hydrogen atoms.

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A student dropped a piece of nickel metal into a solution of HCl(aq). He observed the formation of gas bubbles and collected the

omeli [17]

Answer:

a. The student performed the splint test incorrectly. He should of observed a popping sound when the splint was placed in the test tube.

Explanation:

It is given that a student performed an experiment where he dropped a nickel metal in to HCl solution. He observed the reaction and performed a splint test in the test tube that is filled with a gas which is formed while Nickle is dropped into the solution of HCl.

But the experiment that the student performed was incorrect. He must have observed the popping sound when the splint was placed in the test tube.

When the splint was added to the gas splint flared up. The hydrogen gas pops out when exposed to the flame.

$Ni + HCl(aq) = NiCl + H_2$

Thus the correct option is (a).

5 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m

Bond [772]

Answer:

$m_{H_2O}=4.86gH_2O$

Explanation:

Hello,

In this case, the described chemical reaction is:

$C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O$

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

$n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6$

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

$n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6$

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

$m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O$

Best regards.

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3 years ago

What do the properties of waves moving through aquatic environments tell us about the organisms living in those environments?

pshichka [43]

Assmksksmwmwosmeodmksnsks

7 0

3 years ago

Nvm i have to answer lol

DIA [1.3K]

Answer:

i will do a joke... hmmm...

Explanation:

why did the nurse need a red pen?

To draw out blood. lol

5 0

3 years ago

Read 2 more answers

(a) The student dissolves the entire impure sample of CuSO4(s) in enough distilled water to make 100.mL of solution. Then the st

Talja [164]

Answer:

Explanation:

Given parameters :

Volume of solution = 100mL

Absorbance of solution = 0.30

Unknown:

Concentration of CuSO₄ in the solution = ?

Solution:

There is relationship between the absorbance and concentration of a solution. They are directly proportional to one another.

A graph of absorbance against concentration gives a value of 0.15M at an absorbance of 0.30.

The concentration is 0.15M

Also, we can use: Beer-Lambert's law;

A = ε mC l

where εm is the molar extinction coefficient

C is the concentration

l is the path length

Since the εm is not given and assuming path length is 1;

Then we solve for the concentration.

3 0

3 years ago