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3 years ago

Which molecule contains the smallest number of hydrogen atoms? A) N2H4. B) Al(OH) 3. C) (NH4) 2SO4. D) NH4NO3.

Chemistry

2 answers:

Vesna [10]3 years ago

7 0

The molecule that contains the fewest number of Hydrogen atoms would be B. Al(OH)3. It only has 3 Hydrogen atoms.

Svetach [21]3 years ago

3 0

Answer: Option (B) is the correct answer.

Explanation:

In a molecule of $N_{2}H_{4}$ , there are 2 nitrogen atoms and 4 hydrogen atoms.

In a molecule of $Al(OH)_{3}$ , there are one aluminium atom, three oxygen atoms, and three hydrogen atoms.

In a molecule of $(NH_{4})_{2}SO_{4}$ , there are 2 nitrogen atoms, 8 hydrogen atoms, one sulfur atom and 4 oxygen atoms.

In a molecule of $NH_{4}NO_{3}$ , there are 2 nitrogen atoms, 4 hydrogen atoms and 3 oxygen atoms.

Therefore, we can conclude that out of the given options $Al(OH)_{3}$ is the molecule which contains the smallest number of hydrogen atoms.

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4 years ago

What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?

katen-ka-za [31]

$x= x_{0} e^{kt} ,where~ x ~is~ the ~ |amount\ of \material\ at\ any~~time~t
$
$and~ x_{0} ~the~original~amount.$
$when~x= \frac{12.5}{100} x_{0} }= \frac{125}{1000} x_{0}$
$\frac{x}{ x_{0} } = \frac{125}{1000}= \frac{1}{8}$
$when t=19.8 hrs,
x= x_{0} e^{19.8 k}, 
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ln \frac{1}{8} =19.8 k,
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$ln1-ln8=19.8k,
0-ln 2^{3} =19.8 k,
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k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}$ $x= x_{0} e^{ \frac{-ln2}{6.6}t } ,
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2= e^{ \frac{ln2}{6.6}t } ,
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Answer:

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hope it helps ,pls mark me as brainliest

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