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12345 [234]
3 years ago
9

Which describes the results of the double slit experiment? Check all that apply.

Chemistry
1 answer:
Elanso [62]3 years ago
8 0

Waves produced a diffraction pattern.

Results supported the wave theory of light.

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How much energy is required to heat 40g of water from -7 degrees Celsius to 108 degrees Celsius (Lf= 335,000J/Kg for ice)
solniwko [45]
The   energy  required  to heat  40g  of water  from -7 c  to 108 c is
1541000  joules

     calculation

Q(heat)=  M( mass)  x c(specific heat capacity) xdelta t( change in temperature)

M=  40g=  40/1000= 0.04 Kg
C=  335,000 j/kg/c
delta T   (    108 --7= 115  c)

Q  is therefore   =  0.04 g x  335000 j/kg/c  x 115 c  = 1541,000  joules


6 0
3 years ago
A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the te
Grace [21]

Answer:

The calorimeter constant is  = 447 J/°C

Explanation:

The heat absorbed or released (Q) by water can be calculated with the following expression:

Q = c × m × ΔT

where,

c is the specific heat

m is the mass

ΔT is the change in temperature

The water that is initially in the calorimeter (w₁) absorbs heat while the water that is added (w₂) later releases heat. The calorimeter also absorbs heat.

The heat absorbed by the calorimeter (Q) can be calculated with the following expression:

Q = C × ΔT

where,

C is the calorimeter constant

The density of water is 1.00 g/mL so 50.0 mL = 50.0 g. The sum of the heat absorbed and the heat released is equal to zero (conservation of energy).

Qabs + Qrel = 0

Qabs = - Qrel

Qcal + Qw₁ = - Qw₂

Qcal = - (Qw₂ + Qw₁)

Ccal . ΔTcal = - (cw . mw₁ . ΔTw₁ + cw . mw₂ . ΔTw₂)

Ccal . (30.31°C - 22.6°C) = - [(4.184 J/g.°C) × 50.0 g × (30.31°C - 22.6°C) +  (4.184 J/g.°C) × 50.0 g × (30.31°C - 54.5°C)]

Ccal  = 447 J/°C

5 0
3 years ago
Please help me with this science ​
allochka39001 [22]

Answer:

Allows diffusion of sub...(true)

its found in both anim...(true)

produces en...(false)

4 0
3 years ago
Water boils at 212 degrees
max2010maxim [7]

Answer:

Fahrenheit

Explanation:

Bc i said so LOL JKJK ABAHGTRDSED

5 0
3 years ago
Write the balanced reaction and solubility product expression (KSP) for dissolving silver chromate: Ag2CrO4(s). Include all char
Sonbull [250]

Answer:

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓

Ksp = [2s]²  . [s] → 4s³

Explanation:

Ag₂CrO₄ → 2Ag⁺  + CrO₄⁻²

Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓ Ksp

That's the expression for the precipitation equilibrium.

To determine the solubility product expression, we work with the Ksp

Ag₂CrO₄ (s)  ⇄ 2Ag⁺ (aq)  + CrO₄⁻² (aq)   Ksp

                          2 s                 s

Look the stoichiometry is 1:2, between the salt and the silver.

Ksp = [2s]²  . [s] → 4s³

 

3 0
3 years ago
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