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AnnyKZ [126]
3 years ago
8

Calculate the percent by mass of the solute in an aqueous solution of 27.2 g ethanol in 250 g of total solution.

Chemistry
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

Explanation:

H

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(BRAINLIEST ANSWER GUARANTEED) Write the chemical formula for the following compound
Minchanka [31]

Answer:

HNO3

Explanation:

Try looking up on the internet-

"Science compound creator" and plug in the compounds it gives, and it will give you a formula.

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3 years ago
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The hole in the ozone layer can lead to increases in skin cancer.<br> a. True<br> b. False
Likurg_2 [28]
A. True. The ozone layer is very critical to our health.
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3 years ago
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The daily production of carbon dioxide from an 880 MW coal-fired power plant is estimated to be 31,000 tons. A proposal has been
miskamm [114]

Answer:

1.3578\times 10^{8} m^3 volume of carbon dioxide gas would be collected during a one-year period.

Explanation:

Mass of carbon dioxide gas collected in a day = 31,000 Tonn

1 Tonn = 1000 kilogram

31,000 Tonn = 31,000\times 1000 kg=31,000,000 kg

Specific volume of the carbon dioxide gas = V_s

V_s=0.012 m^3/kg

Volume of carbon dioxide gas collected in a day = V

V=V_s\times 31,000,000 kg=0.012 m^3/kg\times 31,000,000

V=372,000 m^3

1 year = 365 days

Volume of carbon dioxide gas collected in a year = V'

V'=372,000\times 365 m^3=1.3578\times 10^{8} m^3

1.3578\times 10^{8} m^3 volume of carbon dioxide gas would be collected during a one-year period.

5 0
3 years ago
What is the material used to make plaster of paris?​
JulijaS [17]

Answer:

gypsum

Explanation:

gypsum is used to make plaster of Paris

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3 years ago
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An 18 liter container holds 16.00 grams of oxygen gas (o2 at 45 °c. what is the pressure in the container?
Scrat [10]
Hello!

The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is 0,725 atm

To solve this problem we first need to set up the data in the appropriate units to input it in the Ideal Gas Law.

a) 16 g of Oxygen gas to moles of oxygen gas:

16gO_2* \frac{1 mol O_2}{32gO_2}=0,5 mol O_2

b) 45 °C to K

K=$^{\circ}$C + 273,15 = 45 $^{\circ}$C + 273.15=318,15 K

Now, we clear the Ideal Gas Equation for P, and solve it:

P*V=n*R*T \\ \\ P= \frac{n*R*T}{V}= \frac{(0,5mol)*(0,082 \frac{L*atm}{mol*K})* (318,15 K)}{18 L}= 0,725 atm

Have a nice day!
4 0
3 years ago
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