We are given the number of moles of solid magnesium supplied for the reaction which is 0.02 moles while hydrochloric acid is supplied in excess thus we can say that the reaction proceeds to completion. Calculation is as follows:
0.020 mol Mg ( 1 mol H2 / 1 mol Mg ) = 0.020 mol H2 gas is produced
To convert the number of moles to volume, we use the conditions at STP of 1 mol of a substance is equal to 22.4 L. Thus,
0.020 mol H2 (22.4 L / 1 mol) (1000 mL / 1 L) = 448 mL
<h2>That is a <u>Lithium</u> atom!</h2><h3 /><h3>There are THREE protons in that atom. Lithium's atomic number is THREE. If you want to know what isotope that is, look at the neutrons and electrons.</h3><h3 /><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
93.5 moles N₂
Explanation:
To find the moles, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = number of moles
-----> R = constant (0.0821 atm*L/mol*K)
-----> T = temperature (K)
You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.
P = 95.0 atm R = 0.0821 atm*L/mol*K
V = 224 L T = 2773 K
n = ?
PV = nRT
(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)
21280 = n(227.6633)
93.5 = n
D. Being cold temperatures can result in a cold nose. With prolonged exposure The body will start to lose heat faster than it can generate it, this is the result of hypothermia.
2.1653 g
Explanation:
The molar mass of Rubidium is;
85.468 g/mol
Therefore the moles of Rubidium that reacted with oxygen is;
1.98 / 85.468
= 0.0232 moles
If every two moles of Rubidium reacts with one mole of oxygen then the amount of oxygen consumed in the chemical reaction is;
0.5 * 0.0232
= 0.0116 moles
The molar mass of an oxygen atom is 16 g/mole. Then the amount of O in grams consumed is;
0.0116 * 16
=0.1853 g
The final weight of the Rubidium II Oxide is;
1.98 + 0.1853
= 2.1653 g