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V125BC [204]
3 years ago
12

Please help me this is a big grade please

Chemistry
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

water

Explanation:

because the others are in compounds and can not be considered as  products lonely.

You might be interested in
How are atoms of the same element with different mass numbers called?
ELEN [110]

Answer:

Isotopes

Explanation:

Isotopes are the same element with different masses because of the different number of neutrons. Also, the element doesn't change. If we change the protons, the element will change and then it won't be an isotope. Hope it helps!

7 0
3 years ago
How many miles can a commercial jetliner flying at 253 meters per second travel in 6.0 hours
Goryan [66]
1 mile = 1609.344 meters
1 hour = 3600 seconds 345.48 miles per hour x 1609.344
meters/mile x 1hour/3600seconds = 154.44 meter per second~~ANSWERR
6 0
4 years ago
What were the two primary gases in Earth's early atmosphere?
Gemiola [76]
Hydrogen and helium
3 0
3 years ago
A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)
konstantin123 [22]

Answer: norfenefrine (C_8H_{11}NO_2)

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-114.6-(-115.5)^0C=0.9^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant = 1.99^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (ethanol)= density\times volume=0.789g/cm^3\times 1.50cm^3=1.18g=1.18\times 10^{-3}kg

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 82 mg = 0.082 g (1g=1000mg)

0.9=1\times 1.99\times \frac{0.082g}{M g/mol\times 1.18\times 10^{-3}}kg}

M=154g/mol

The molecular mass of norfenefrine (C_8H_{11}NO_2) is near to 154 and thus the identity of the white powder is norfenefrine .

4 0
3 years ago
What is the expected major organic product from the treatment of 4-methyl-2-pentyne with excess hydrogen in the presence of a pl
tatiyna

Answer:

(Z)-4-methyl-2-pentene

Explanation:

Hydrogenation  is a syn addition. This implies that the hydrogen atoms add to the same face of the multiple bond.

Hence, if we have the alkyne,  4-methyl-2-pentyne which reacts with excess hydrogen in the presence of a platinum catalyst, we obtain  (Z)-4-methyl-2-pentene since the hydrogen atoms add on the same side of the multiple bond.

6 0
3 years ago
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