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3 years ago

How far should the second antenna be moved in order to receive a minimum signal from a station that broadcasts at 99.4 MHz?

Physics

1 answer:

raketka [301]3 years ago

5 0

Answer:

So the distance of the antenna from the station will be 3.018 m

Explanation:

We have given the frequency of the broadcast $f=99.4MHz=99.4\times 10^4Hz$

The speed of light $c=3\times 10^8m/sec$

The distance of the antenna to receive a minimum signal from the station is given by $d=\frac{v}{f}=\frac{3\times 10^{8}}{99.4\times 10^6}=3.018m$

So the distance of the antenna from the station will be 3.018 m

You might be interested in

Starting from one oasis, a camel walks 25 km in a direction 30° south of west and then walks 30 km toward the north to a second

shepuryov [24]

Answer:

distance between both oasis ( 1 and 2) is 27.83 Km

Explanation:

let d is the distance between oasis1 and oasis 2

from figure

OC = 25cos 30

OE = 25sin30

OE = CD

Therefore BC = 30-25sin30

distance between both oasis ( 1 and 2) is calculated by using phytogoras theorem

in $\Delta BCO$

$OB^2 = BC^2 + OC^2$

PUTTING ALL VALUE IN ABOVE EQUATION

$d^2 = 930-25sin30)^2 + (25cos30)^2$

$d^2 = 775$

d = 27.83 Km

distance between both oasis ( 1 and 2) is 27.83 Km

3 0

2 years ago

A combustion reaction usually gives off heat and light is it true or false

yanalaym [24]

The answer is true I think

3 0

3 years ago

A scientist reports a measurement of the temperature of the surface of a newly discovered planet as negative 20 Kelvin. What con

jarptica [38.1K]

Answer:

The temperature of this newly discovered planet violates the third law of thermodynamic, there is a mistake in this value.

Explanation:

The third law of the Thermodynamic says:

<u> At zero kelvin all molecular movement stops, which means that the entropy will be zero at this temperature.</u>

So we can say there is no thermodynamic system that has temperature values less than 0 K.

The conclusion of the report will be.

The temperature of this new planet violates the third law of thermodynamic, there is a mistake in this value.

I hope it helps you!

3 0

2 years ago

A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

PIT_PIT [208]

Their velocity afterward is v=3.467 m/s

Explanation:

Given:

Mass of the first football player= 91.5 kg

Initial velocity of the football player 3.73 m/s

Mass of second football player=63.56 kg

Initial velocity of the second football player=3.09 m/s

To find:

Final velocity of both players=?

Solution:

According to the law of conservation of momentum,

Initial momentum =final momentum

mathematically represented as

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$ ...........................(1)

where

$u_1$ =intial velocity of the football player

$u_2$ = inital velocity of second football player

$v_1$ =finall velocity of the first football player

$v_2$ =final velocity of second football player

after tackling , both the football players moves with the same velocity,

so $v_1=v_2=v$

Hence equation (1) becomes

$m_1u_1+m_2u_2=(m_1+m_2)v$

$v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}$

now substituting the values,

$v=\frac{(91.5\times+3.73)+(63.5\times3.09)}{(91.5+63.5)}$ $v=\frac{(341.29+196.210)}{155}$

$v=\frac{537.5}{155}$

v=3.467 m/s

7 0

3 years ago

Can somebody answer this for me asap!

andreev551 [17]

It shows all except the types of precipitation and created for newspapers

7 0

2 years ago