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irinina [24]
4 years ago
8

What would be the density if a nugget of gold’s mass of 965g and a volume of 50cm

Chemistry
2 answers:
Ulleksa [173]4 years ago
5 0

Answer:

19.3 g/cm³

Explanation:

\text{Density} = \frac{\text{mass}}{\text{volume}}

Mass = 965 g; volume = 50 cm³. So,  

\text{Density} =\frac{\text{965 g}} {\text{50 cm}^{3}} = \text{19.3 g/cm}^{3}

olchik [2.2K]4 years ago
3 0

p = 19.3 g/cm3


V√3=3.6840315cm :))

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What force must act on a 150 kg mass to give it an acceleration of 30 m/s squared? F=ma
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Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

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On melting of ice , there is a decrease in volume instead of increase . Why ?
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