All categories

3 years ago

In an endothermic reaction what is true of the enthalpy

Chemistry

1 answer:

charle [14.2K]3 years ago

4 0

Answer is: a) is has increased.

There are two types of reaction:

1) endothermic reaction (chemical reaction that absorbs more energy than it releases).

For example, the breakdown of ozone is an endothermic process. Ozone has lower energy than molecular oxygen (O₂) and oxygen atom, so ozone need energy to break bond between oxygen atoms.

2) exothermic reaction (chemical reaction that releases more energy than it absorbs).

For example, ΔH(reaction) = -225 kJ/mol; this is exothermic reaction.

You might be interested in

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)

stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of O₂(g) produces 3 moles of CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1 : 3

What about ;

? (x) : 1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 : 3

What about

? (x) : 1

3x = 5 * 1

x = 5/3

Learn More:

For more on evaluating moles in chemical reactions check out;

brainly.com/question/13967925

brainly.com/question/13969737

#LearnWithBrainly

7 0

3 years ago

Which of the following measurements is equal to 2.3 dL?

Nonamiya [84]

What are the following measurements?

6 0

3 years ago

4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration

anzhelika [568]

Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

$percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100$

<u><em>percentage composition of potassium iodide= 0.017%</em></u>

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

brainly.com/question/24201923

brainly.com/question/9779410

brainly.com/question/17030163

#SPJ1

3 0

2 years ago

You need 455 ml of a 75% alcohol solution. on hand, you have a 25% alcohol mixture. you also have a 90% alcohol mixture. how muc

marishachu [46]

X ml - <span>25% alcohol mixture
y ml - </span><span>90% alcohol mixture

x+y = 455

0.25x ml alcohol in </span>x ml of 25% alcohol mixture
0.9y ml alcohol in y ml of  90% alcohol mixture
0.75*455= 341.25 ml alcohol in 455 ml of  75% alcohol mixture

0.25x+0.9y=341.25

System of equations:

x+y = 455 /*(-0.25) ------> -0.25x-0.25y = -0.25*455
0.25x+0.9y=341.25

-0.25x-0.25y=-113.75
0.25x+0.9y=341.25 Add both equations

0.25x+0.9y-0.25x-0.25y=341.25-113.75
0.65y =227.5
y=227.5/0.65 = 350 ml  of  90% alcohol mixture

x+y=455
x+355=455
x=100 ml of  25% alcohol mixture

8 0

3 years ago

1s22s22p63s23p6 How many unpaired electrons are in the atom represented by the electron configuration above?

pickupchik [31]

Answer:

Explanation:

There are no unpaired electrons in the given element. It must be noted that for the atom above, we have even numbered electrons. The total electron we are having here is 18.

Now, we must also know that while the s orbital is not degenerate, the P orbital is degenerate. What this mean is that the p orbital is broken down into three different sub orbitals which is the Px , Py and Pz. Hence we can see that there are 6 electrons to enter into the P orbital too.

We can see that all the S orbitals have been completely filled with two electrons alike each. This is also the case for the P orbital as the 3 suborbitals take in 2 each to give a total of six

4 0

3 years ago