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mezya [45]
3 years ago
9

When oxygen is available what happens immediately after glycolysis?

Chemistry
1 answer:
vekshin13 years ago
3 0

Answer:

NADH is formed

Explanation:

If oxygen exists in the system, pyruvate goes into mitochondrial matrix in order to perform kreb's cycle and forms NADH

Otherwise, pyruvate forms into lactate acid.

Good luck on your final exam

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There are two atoms of sodium and one atom of oxygen.

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The weak base ionization<br> constant (Kb) for HCO3 is<br> equal to:
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Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.

<h3>What is a weak base ionization constant?</h3>

The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.

The reaction for HCO₃ is given as:

HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O

The value of Ka for the given reaction will be:

Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]

Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.

Learn more about the weak ionization constant here:

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A geothermal power plant can be used to generate electricity:
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What subatomic particles do the following symbols represent in the atomic diagrams
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Indicate whether either an increase or decrease of pressure obtained by changing the volume would increase the amount the produc
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Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle:

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On an increase in the volume :

If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place.And equilibrium will shift in direction where number of gaseous moles are more.

On an decrease in the volume :

If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decease in pressure is taking place.And equilibrium will shift in direction where number of gaseous moles are less.

a. CO(g) + 2 H_2(g)\rightleftharpoons CH_3OH(g)

On an increase in the volume :

As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to  increase the amount of product we have to increase the pressure of the reactants molecules decrease the volume.

b.2SO_2(g) +O_2(g) \rightleftharpoons 2SO_3(g)

As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to  increase the amount of product we have to increase the pressure of the reactants molecules decrease the volume.

c. 2NO_2(g)\rightleftharpoons N_2O_4(g)

As the number of moles of gas molecules is greater at the reactant side. So, the equilibrium will shift in the left direction. So in order to  increase the amount of product we have to increase the pressure of the reactants molecules and decrease the volume .

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