We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is
but this would imply that
, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have
and solving gives
, which makes more sense. Then the number of extra spades in the deck must be 2.
0745 legit is 7:45 in military time
No, because -15 have 2 corresponding elements .
Answer:
$1800
Step-by-step explanation:
Volume of the foundation: 30*12*6 = 2160 cubic feet
we need to convert this into yards because a truckload is 8 cubic yards, 2160/3 = 720 cubic yd
One truckload is 8 cubic yards
# of truckloads needed: 720/8 = 90 truckloads
Cost: $20*90 = $1800
Answer:
Cost of a pound of chocolate chips: $3.5
Cost of a pound of walnuts: $1.25
Step-by-step explanation:
x - cost of a pound of chocolate chips
y - cost of a pound of walnuts
We create two equations based on the information we have:
3x+2y=13
8x+4y=33
The whole point of these problems os to get rid of x or y. In this question, we can do this by multiplying both sides of the first equation by 2, and then subtracting it from the second equation:
8x+4y=33
6x+4y=26
2x=7
x=3.5
Then we change x for 3.5 in the first equation:
3×3.5+2y=13
10.5+2y=13
2y=2.5
y=1.25
Hope this helps!
