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Liono4ka [1.6K]

3 years ago

8

Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of

solution? Use mc006-1.jpg. 0.333 M 0.751 M 1.50 M 3.00 M

2 answers:

jenyasd209 [6]3 years ago

7 0

I hope it cleared your doubt.

Stells [14]3 years ago

4 0

<u>Given information:</u>

Mass of NaCl (m) = 87.75 g

Volume of solution (V) = 500 ml = 0.5 L

Molar mass of NaCl (M) = 58.44 g/mol

<u>To determine:</u>

The molarity of NaCl solution

<u>Explanation:</u>

Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)

i.e. M = moles of solute/liters of solution = n/V

Moles of solute (n) = mass of solute (m)/molar mass (M)

moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles

Therefore,

Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M

<u>Ans: (D)</u>

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<u>Explanation:</u>

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<u>For 2:</u>

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<u>For 5:</u>

We are given:

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<u>For 6:</u>

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