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Romashka [77]
3 years ago
6

1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol

Chemistry
2 answers:
romanna [79]3 years ago
6 0

Answer:

Density is independent variable and mass is dependent variable.

A. 1.015 g/mL is the density of the ethylene glycol solution.

B. 16.378 mol/L is the molarity of the ethylene glycol solution.

Explanation:

Independent variable is defined as the variable which remain as such and has no effect on the change of another variable. For

Dependent variable is defined as the variable whose value varies with respect to any other variable.

Density is an independent factor as one can determine it by the slope of graph of mass verses volume. Density will remain same on changing the mass of the substance.

Where as mass of ethylene glycol is dependent  variable.

A. Mass of volumetric flask with stopper = 32.6341 g

Mass of volumetric flask, stopper and ethylene glycol =  58.0091 g

Mass of ethylene glycol = 58.0091 g - 32.6341 g =25.3751 g

Volume of the volumetric flask = 25 mL

Density=\frac{Mass}{Volume}

Density of ethylene glycol = D

D=\frac{25.3751 g}{25 mL}=1.015 g/mL

B. Molarity=\frac{Moles}{Volume(L)}

Moles of ethylene glycol ,n = \frac{25.3751 g}{62 g/mol}=0.4093 mol

Volume of the solution = V = 25 mL = 0.025 L

Molarity =\frac{0.4093 mol}{0.025 mL}=16.37 mol/L

AnnyKZ [126]3 years ago
5 0
<span>1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol
The independent variable would be ethylene glycol and dependent variable would be density.

A. A 25-mL volumetric flask with its stopper has a mass of 32.6341 g. The same flask filled to the line with ethylene glycol (C2H6O2, automotive antifreeze) solution has a mass of 58.0091 g. What is the density of the ethylene glycol solution?

Density = 58.0091 - 32.6341 / .025 = 1015 g/L

B. What is the molarity of the ethylene glycol solution, if the mass of ethylene glycol in the solution is 12.0439 g?

Molarity = 12.0439 ( 1 mol / 62.07 g) / 0.025 = 7.8 M</span>
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Simora [160]

The carbon would be your answer hope this helps

4 0
3 years ago
What mass of HgO is required to produce 0.692 mol of O2?<br><br>2HgO(s) -&gt; 2Hg(l) + O2(g)
Vika [28.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO  → 2 Hg + O_{2}

where,

HgO represents mercuric oxide

Hg represents mercury

O_{2} represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

molar mass of oxygen (O) =16 grams

HgO = 200 +16 = 216 grams

We know;

       2×216 grams of HgO   →  1 mole of oxygen molecule

             ?                              →  0.692 moles of oxygen molecule

       

          = \frac{2*216*0.692}{1}

      = 298.944 grams of HgO

<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

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7 0
3 years ago
Read 2 more answers
Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,
8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

6 0
3 years ago
Please help ASAP
marta [7]

Answer:

0.1

Explanation:

We must first put down the equation of the reaction in order to guide our solution of the question.

2HNO3(aq) + Sr(OH)2(aq) -------> Sr(NO3)2(aq) + 2H2O(l)

Now from the question, the following were given;

Concentration of acid CA= ??????

Concentration of base CB= 0.299M

Volume of acid VA= 17.8ml

Volume of base VB= 24.7ml

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CA= CBVBNA/VANB

SUBSTITUTING VALUES;

CA= 0.299 × 24.7 ×2 / 17.8×1

CA= 0.8298 M

But;

pH= -log[H^+]

[H^+] = 0.8298 M

pH= -log[0.8298 M]

pH= 0.1

5 0
3 years ago
Please help me it’s my birthday
GalinKa [24]

Answer:

ur answer would be D.)

Explanation:

Hope this helps

also happy birthday

5 0
3 years ago
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