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tatuchka [14]
3 years ago
11

The mean of data set A is 42. The mean of data set B is 47. The mean absolute deviation (MAD) of both data sets is 2.5. What is

the difference of the means?
Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

the difference of the mean in the case of mean absolute deviation is 2.5

Step-by-step explanation:

The computation of the difference of the mean is shown below:

Difference is of

= B - A

= 47 - 42

= 5

Now the difference of the mean is

= 5 ÷ 2.5

= 2.5

Hence, the difference of the mean in the case of mean absolute deviation is 2.5

The same would be relevant

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Zigmanuir [339]

Answer: 102 foot / feet tall

Step-by-step explanation:

First, we have to find the unit rate . . . what is 24 divided by 20 ? 1.2/1

Second, multiply . . . what is 1.2 x 85 ? 102

( sorry if this is wrong - I forgot how to do the second part for a sec )

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juin [17]
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8 0
3 years ago
-2b+2(b-10)=2(10+5b)
alina1380 [7]

Answer:

b= -4

Step-by-step explanation:

On both sides of the equation has distributive property. We need to solve that first. Let's start with the left side of the equation.

*Positive multiplied by a negative equals a negative

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-2b+2b-20= 2(10+5b)

-20= 2(10+5b)

Now let's solve the right side of the equation

-20= 20+10b

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Hope this helps!

5 0
3 years ago
15. PLEASE HELP ME
Nana76 [90]
  • Surface Area=7238in^2

We know

\boxed{\sf Surface\:area=4\pi r^2}

\\ \sf\longmapsto 4\pi r^2=7238

\\ \sf\longmapsto 4\times \dfrac{22}{7}r^2=7238

\\ \sf\longmapsto r^2=\dfrac{7238\times 7}{88}

\\ \sf\longmapsto r^2=\dfrac{5066}{88}

\\ \sf\longmapsto r^2=575.75

\\ \sf\longmapsto r^2\approx576

\\ \sf\longmapsto r\approx\sqrt{576}

\\ \sf\longmapsto r\approx24in

<h3>Option b is coreect</h3>
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Answer:

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