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melamori03 [73]
3 years ago
11

HELP PLEASE! THANKS!!

Physics
2 answers:
Tpy6a [65]3 years ago
7 0
The only logical answer is B
aniked [119]3 years ago
6 0

Answer:

The answer is B. hope this helped

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A jet aircraft is traveling at 262 m/s in hor-
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Solution :

Speed of the air craft, $S_a$ = 262 m/s

Fuel burns at the rate of, $S_b$ = 3.92 kg/s

Rate at which the engine takes in air, $S_{air}$ = 85.9 kg/s

Speed of the exhaust gas that are ejected relative to the aircraft, $S_{exh}$ =921 m/s

Therefore, the upward thrust of the jet engine is given by

$F=S_{air}(S_{exh}-S_a)+(S_b \times S_{exh})$

F = 85.9(921 - 262) + (3.92 x 921)

   = 4862635.79 + 3610.32

   = $4.8 \times 10^6 \ N$

Therefore thrust of the jet engine is $4.8 \times 10^6 \ N$.

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2 years ago
The curved section of a horizontal highway is a circular unbanked arc of radius 740 m. If the coefficient of static friction bet
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The answer would be 54 m/s as the maximum speed
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A thunderstorm loses energy in the _______ stage.
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Calculate the time it would take a motor with a power of 0.6kW to lift a suitcase of 20kg a distance of 50cm
True [87]

Answer:

0.163 s

Explanation:

Appying,

P = mgh/t................ Equation 1

Where P = power of the motor, m = mass of the suitcase, h = vertical distance, t = time, g = acceleration due to gravity.

make t the subject of the equation,

t = mgh/P................ Equation 2

Given: m = 20 kg, h = 50 cm = 0.5 m, P = 0.6 kW = 600 W

Constant: g = 9.8 m/s²

Substitute these values into equation 2

t = (20×0.5×9.8)/600

t = 0.163 s

7 0
2 years ago
A shooting star is actually the track of a meteor, typically a small chunk of debris from a comet that has entered the earth's a
s2008m [1.1K]

Answer:

A. Power generated by meteor = 892857.14 Watts

Yes. It is obvious that the large amount of power generated accounts for the glowing trail of the meteor.

B. Workdone = 981000 J

Power required = 19620 Watts

Note: The question is incomplete. A similar complete question is given below:

A shooting star is actually the track of a meteor, typically a small chunk of debris from a comet that has entered the earth's atmosphere. As the drag force slows the meteor down, its kinetic energy is converted to thermal energy, leaving a glowing trail across the sky. A typical meteor has a surprisingly small mass, but what it lacks in size it makes up for in speed. Assume that a meteor has a mass of 1.5 g and is moving at an impressive 50 km/s, both typical values. What power is generated if the meteor slows down over a typical 2.1 s? Can you see how this tiny object can make a glowing trail that can be seen hundreds of kilometers away? 61. a. How much work does an elevator motor do to lift a 1000 kg elevator a height of 100 m at a constant speed? b. How much power must the motor supply to do this in 50 s at constant speed?

Explanation:

A. Power = workdone / time taken

Workdone = Kinetic energy of the meteor

Kinetic energy = mass × velocity² / 2

Mass of meteor = 1.5 g = 0.0015 kg;

Velocity of meteor = 50 km/s = 50000 m/s

Kinetic energy = 0.0015 × (50000)² / 2 = 1875000 J

Power generated = 1875000/2.1 = 892857.14 Watts

Yes. It is obvious that the large amount of power generated accounts for the glowing trail of the meteor.

B. Work done by elevator against gravity = mass × acceleration due to gravity × height

Work done = 1000 kg × 9.81 m/s² × 100 m

Workdone = 981000 J

Power required = workdone / time

Power = 981000 J / 50 s

Power required = 19620 Watts

Therefore, the motor must supply a power of 19620 Watts in order to lift a 1000 kg to a height of 100 m at a constant speed in 50 seconds.

6 0
3 years ago
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