Answer:
0.74 m/s
Explanation:
given,
time taken by the ramp to cover cliff , t = 64 s
acceleration = 0.37 m/s²
distance traveled by the belt
![x = v_{belt}t_{belt}](https://tex.z-dn.net/?f=x%20%3D%20v_%7Bbelt%7Dt_%7Bbelt%7D)
Clifford is moving with constant acceleration
...(1)
initial velocity is equal to zero
........(2)
equating equation (1) and (2)
![v_{belt}t_{belt}=\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=v_%7Bbelt%7Dt_%7Bbelt%7D%3D%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
![v_{belt}t_{belt}=\dfrac{1}{2}a(\dfrac{1}{4}\times t_{belt})^2](https://tex.z-dn.net/?f=v_%7Bbelt%7Dt_%7Bbelt%7D%3D%5Cdfrac%7B1%7D%7B2%7Da%28%5Cdfrac%7B1%7D%7B4%7D%5Ctimes%20t_%7Bbelt%7D%29%5E2)
![v_{belt}=\dfrac{1}{32}a t_{belt}](https://tex.z-dn.net/?f=v_%7Bbelt%7D%3D%5Cdfrac%7B1%7D%7B32%7Da%20t_%7Bbelt%7D)
![v_{belt}=\dfrac{1}{32}\times 0.37 \times 64](https://tex.z-dn.net/?f=v_%7Bbelt%7D%3D%5Cdfrac%7B1%7D%7B32%7D%5Ctimes%200.37%20%5Ctimes%2064)
![v_{belt}= 0.74\ m/s](https://tex.z-dn.net/?f=v_%7Bbelt%7D%3D%200.74%5C%20m%2Fs)
Speed of the belt is equal to 0.74 m/s
Answer:
1375km?
Explanation:
i think that is the answer
Answer:
a) p = 95.66 cm, b) p = 93.13 cm
Explanation:
For this problem we use the constructor equation
where f is the focal length, p and q are the distances to the object and the image, respectively
the power of the lens is
P = 1 / f
f = 1 / P
f = 1 / 2.25
f = 0.4444 m
the distance to the object is
the distance to the image is
q = 85 -2
q = 83 cm
we must have all the magnitudes in the same units
f = 0.4444 m = 44.44 cm
we calculate
1 / p = 0.010454
p = 95.66 cm
b) if they were contact lenses
q = 85 cm
1 / p = 0.107375
p = 93.13 cm
a. θ = 41. 4°
b. θ = 60°
c. θ = 75. 5°
d. θ = 90°
<h3>How to determine the angle</h3>
From the given information, we would be using the Malus' law
It is given as;
I = I0 cos²θ
Where I0 is the intensity of the polarized light after passing through P
a. To find the angle, compare with the given equation
I = (0.750)I0
I = I0 cos θ
then
cos θ = 0. 750
θ = ![cos^-^1(0. 750)](https://tex.z-dn.net/?f=cos%5E-%5E1%280.%20750%29)
θ = 41. 4°
b. I = (0.500)I0
cos θ = 0. 500
θ = ![cos^-^1(0. 500)](https://tex.z-dn.net/?f=cos%5E-%5E1%280.%20500%29)
θ = 60°
c. I = (0.250)I0
cos θ = 0. 250
θ = ![cos^-^1 (0. 250)](https://tex.z-dn.net/?f=cos%5E-%5E1%20%280.%20250%29)
θ = 75. 5°
d. I = 0
cos θ = 0
θ = ![cos^-^1 (0)](https://tex.z-dn.net/?f=cos%5E-%5E1%20%280%29)
θ = 90°
Learn more about light intensity here:
brainly.com/question/19791748
#SPJ1
Answer: composition, its size and shape.
Explanation:
All objects have <u>a frequency that characterizes them</u>, which is called <u>natural frequency</u>. This means that if a disturbance or vibration is emitted near the object, it will begin to vibrate due to its natural frequency.
It should be noted that there are objects that have more than one natural frequency, and this depends on the composition of the object, its elasticity, its shape and size.